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3 years ago

Given the point (4,5) and the slope of 6 find y and when x=24

Mathematics

1 answer:

mixas84 [53]3 years ago

7 0

You multiply 6 and 24 then add 5. So, you get d.

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2x +4 (3 - 2x) = 3(2x + 2)/6 + 4<br> from my math book

liberstina [14]

Answer:

x = 1

Step-by-step explanation:

2x +4 (3 - 2x) = 3(2x + 2)/6 + 4

2x+12-8x = (6x+6)/6 +4

-6x + 12 = x+1+4

12-5 = 7x

7x = 7

x=1

Hope this helps!

4 0

2 years ago

Read 2 more answers

Which number could be added to

Arturiano [62]

The number which could be added to both sides of the equation to complete the square is; -2.25.

<h3>Which number could be added to both sides of this quadratic equation to complete the square?</h3>

The quadratic equations give in the task content is; 1=x²-3x. Hence, to express the equation by completing the square method; we have;

1 - 2.25 = (x -3/2)² - 2.25

Hence, the number which should be added to both sides of the equation is; -2.25.

Read more on completing the square;

brainly.com/question/10449635

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3 0

2 years ago

A home improvement store normally sells 20-foot extension ladders for $225. This week the ladders are discounted by 20%. What is

Fantom [35]

Answer:

The answer is 180

Step-by-step explanation:

So to start off you have to turn 20% into a decimal and that is .20.

Next you need to mutiply 225 and .20 and you will get 45 (that means it is $45 off)

Subtract 45 fro 225 and that is your answer.

You now pay $180 for the 20 foot extension ladder.

5 0

3 years ago

The probability that an American CEO can transact business in a foreign language is .20. Twelve American CEOs are chosen at rand

NNADVOKAT [17]

Answer with Step-by-step explanation:

We are given that

The probability that an American CEO can transact business in foreign language=0.20

The probability than an American CEO can not transact business in foreign language= $1-0.20=0.80$

Total number of American CEOs chosen=12

a. The probability that none can transact business in a foreign language= $12C_0(0.20)^0(0.80)^{12}$

Using binomial theorem $nC_r(1-p)^{n-r}p^r$

The probability that none can transact business in a foreign language= $\frac{12!}{0!(12-0)!}(0.8)^{12}=(0.8)^{12}$

b.The probability that at least two can transact business in a foreign language= $1-P(x=0)-p(x=1)=1-((0.8)^{12}+12C_1(0.8)^{11}(0.2))=1-((0.8)^{12}+12(0.8)^{11}}(0.2))$