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love history [14]
3 years ago
12

Simplify. -x/17 = -0.9 a. -15.3 b. 15.3 c. 153 d. -153

Mathematics
1 answer:
sergejj [24]3 years ago
7 0

Answer:

\large\boxed{b.\ 15.3}

Step-by-step explanation:

-\dfrac{x}{17}=-0.9\qquad\text{multiply both sides by (-17)}\\\\(-17\!\!\!\!\!\diagup^1)\left(-\dfrac{x}{17\!\!\!\!\!\diagup_1}\right)=(-17)(-0.9)\qquad{/(-)(-)=(+)/}\\\\x=15.3

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Simplify the expression using the exponent properties 5 ^ −4 x 5^ −3
vodka [1.7K]

Answer:

5^{-7} or 0.0000128

Step-by-step explanation:

Add the exponents together

-4+-3=-7

3 0
3 years ago
Evaluate the limit with either L'Hôpital's rule or previously learned methods.lim Sin(x)- Tan(x)/ x^3x → 0
Vsevolod [243]

Answer:

\dfrac{-1}{6}

Step-by-step explanation:

Given the limit of a function expressed as \lim_{ x\to \ 0} \dfrac{sin(x)-tan(x)}{x^3}, to evaluate the following steps must be carried out.

Step 1: substitute x = 0 into the function

= \dfrac{sin(0)-tan(0)}{0^3}\\= \frac{0}{0} (indeterminate)

Step 2: Apply  L'Hôpital's rule, by differentiating the numerator and denominator of the function

= \lim_{ x\to \ 0} \dfrac{\frac{d}{dx}[ sin(x)-tan(x)]}{\frac{d}{dx} (x^3)}\\= \lim_{ x\to \ 0} \dfrac{cos(x)-sec^2(x)}{3x^2}\\

Step 3: substitute x = 0 into the resulting function

= \dfrac{cos(0)-sec^2(0)}{3(0)^2}\\= \frac{1-1}{0}\\= \frac{0}{0} (ind)

Step 4: Apply  L'Hôpital's rule, by differentiating the numerator and denominator of the resulting function in step 2

= \lim_{ x\to \ 0} \dfrac{\frac{d}{dx}[ cos(x)-sec^2(x)]}{\frac{d}{dx} (3x^2)}\\= \lim_{ x\to \ 0} \dfrac{-sin(x)-2sec^2(x)tan(x)}{6x}\\

=  \dfrac{-sin(0)-2sec^2(0)tan(0)}{6(0)}\\= \frac{0}{0} (ind)

Step 6: Apply  L'Hôpital's rule, by differentiating the numerator and denominator of the resulting function in step 4

= \lim_{ x\to \ 0} \dfrac{\frac{d}{dx}[ -sin(x)-2sec^2(x)tan(x)]}{\frac{d}{dx} (6x)}\\= \lim_{ x\to \ 0} \dfrac{[ -cos(x)-2(sec^2(x)sec^2(x)+2sec^2(x)tan(x)tan(x)]}{6}\\\\= \lim_{ x\to \ 0} \dfrac{[ -cos(x)-2(sec^4(x)+2sec^2(x)tan^2(x)]}{6}\\

Step 7: substitute x = 0 into the resulting function in step 6

=  \dfrac{[ -cos(0)-2(sec^4(0)+2sec^2(0)tan^2(0)]}{6}\\\\= \dfrac{-1-2(0)}{6} \\= \dfrac{-1}{6}

<em>Hence the limit of the function </em>\lim_{ x\to \ 0} \dfrac{sin(x)-tan(x)}{x^3} \  is \ \dfrac{-1}{6}.

3 0
3 years ago
5d-2/3c if d =4 and c =3 evaluate fast fast
Mademuasel [1]

Answer:

2

Step-by-step explanation:

Plug 4 in for d and 3 in for c

5d-2/3c

5(4)-2/3(3)

Multiply in the numerator and the denominator

20-2/9

Subtract in the numerator

18/9

2

Hope this helps! :)

4 0
3 years ago
(x−3)÷9=11<br> help idk how to do this
Bess [88]

Answer:

102

Step-by-step explanation:

papa math will help you

x−3

9

=11

Step 1: Multiply both sides by 9.

x−3

9

=11

(

x−3

9

)*(9)=(11)*(9)

x−3=99

Step 2: Add 3 to both sides.

x−3+3=99+3

x=102

Answer:

x=102

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https://www.mathpapa.com/algebra-calculator.html?q=(x%E2%88%923)%5Cdiv9%3D11

x−3

9

=11

Step 1: Multiply both sides by 9.

x−3

9

=11

(

x−3

9

)*(9)=(11)*(9)

x−3=99

Step 2: Add 3 to both sides.

x−3+3=99+3

x=102

Answer:

x=102

Close Ad

Back to Algebra Calculator »

Share this page

Share URL:

https://www.mathpapa.com/algebra-calculator.html?q=(x%E2%88%923)%5Cdiv9%3D11

x−3

9

=11

Step 1: Multiply both sides by 9.

x−3

9

=11

(

x−3

9

)*(9)=(11)*(9)

x−3=99

Step 2: Add 3 to both sides.

x−3+3=99+3

x=102

Answer:

x=102

Close Ad

Back to Algebra Calculator »

Share this page

Share URL:

https://www.mathpapa.com/algebra-calculator.html?q=(x%E2%88%923)%5Cdiv9%3D11

6 0
3 years ago
An experienced cashier at a grocery store takes 2 seconds to scan each item and 40 seconds to process the customer's payment. 1)
grigory [225]

Answer:

The correct option is D) 43 items.

Step-by-step explanation:

As we know that total given time is ,

Y = (60\times2) +6 =126\hspace{0.15cm} sec,

Out of which cashier spends 40 seconds to process the customer's payment.

So the remaining time = (126 - 40) = 86 secs.

And the remaining time is used to scan the item and so that we can calculate here the no items scan is = (86 ÷ 2) = 43.

Therefore we can say that 43 items are being purchased.

6 0
3 years ago
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