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3 years ago

Of the 24 students in Greg's class, 3/8 ride the bus to school. How many students ride the bus?

Mathematics

2 answers:

tresset_1 [31]3 years ago

8 0

I believe 9 students rides the bus
3/8 x 24= 9

Paladinen [302]3 years ago

7 0

1 cuz 24 divided by 3/8 = 1

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The mathematics department of a college has 15 male professors, 9 female professors, 6 male teaching assistants, and 12 female t

Vesnalui [34]

Given:

The number of male professors = 15.

The number of female professors = 9.

The number of male teaching assistants = 6.

The number of female teaching assistants = 12.

A person is selected randomly from the group.

Required:

We need to find the probability that the selected person is a professor or a male.

Explanation:

The total number of people in the group = 15+9+6+12 = 42

n(S) =The total number of people in the group

$n(S)=42$

Let A be the event that the selected person is a professor or a male.

The number of people who are professors or male = 15+9+6 = 30

n(A)= The number of people who are professors or male.

$n(A)=30$

Let P(A) be the probability that the selected person is a professor or a male.

$P(A)=\frac{n(A)}{n(S)}$ $P(A)=\frac{30}{42}$ $P(A)=\frac{15}{21}=\frac{5}{7}$

Final answer:

The probability that the selected person is a professor or a male is 5/7.

7 0

1 year ago

HELP PLEASEEE Angle M' is the result of its pre-image, angle sliding horizontally in a direction and vertically in a direction.

Kobotan [32]

Answer:

angle M

horizontally in a positive

vertically in a positive

4 0

3 years ago

Circle C has radius 5 and center C(6,-2). What is the equation of circle C ?

Delvig [45]

Answer:

i guess it is d

Step-by-step explanation:

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4 0

3 years ago

Pls ,pls,plssss help my

Mumz [18]

plsss go ahead and tell your problem

5 0

3 years ago

Pls help :)) this question is confusing for me :)

Temka [501]

Given:

$y^{2}(2 y-5)-8 y+20$

To find:

The product of the expression.

Solution:

$y^{2}(2 y-5)-8 y+20=y^{2}(2 y-5)+(-8 y+20)$

Take out -4 as a common factor in Last two terms.

$=y^{2}(2 y-5)-4(2 y-5)$

Make sure the terms in both brackets must be same.

Take out common factor (2y - 5) from both terms.

$=(2 y-5)(y^{2}-4)$

4 can be written as 2².

$=(2 y-5)\left(y^{2}-2^2\right)$

Using the identity: $(a^2-b^2)=(a-b)(a+b)$

$=(2 y-5)(y-2)(y+2)$ .

The product is $(2 y-5)(y-2)(y+2)$ .

5 0

3 years ago