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Softa [21]
3 years ago
7

You know that 5^2=25. How can you use this fact to evaluate 5^4

Mathematics
1 answer:
PIT_PIT [208]3 years ago
7 0

Answer:

5^4 = 625

Step-by-step explanation:

5^4 is just 25 times 25

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Compare the fraction negative 6/7 (?) 1/7
jeyben [28]
-6/7<1/7
A negative is always less than a positive number.
8 0
3 years ago
Find the? inverse, if it? exists, for the given matrix.<br><br> [4 3]<br><br> [3 6]
True [87]

Answer:

Therefore, the inverse of given matrix is

=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}

Step-by-step explanation:

The inverse of a square matrix A is A^{-1} such that

A A^{-1}=I where I is the identity matrix.

Consider, A = \left[\begin{array}{ccc}4&3\\3&6\end{array}\right]

\mathrm{Matrix\:can\:only\:be\:inverted\:if\:it\:is\:non-singular,\:that\:is:}

\det \begin{pmatrix}4&3 \\3&6\end{pmatrix}\ne 0

\mathrm{Find\:2x2\:matrix\:inverse\:according\:to\:the\:formula}:\quad \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}^{-1}=\frac{1}{\det \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}}\begin{pmatrix}d\:&\:-b\:\\ -c\:&\:a\:\end{pmatrix}

=\frac{1}{\det \begin{pmatrix}4&3\\ 3&6\end{pmatrix}}\begin{pmatrix}6&-3\\ -3&4\end{pmatrix}

\mathrm{Find\:the\:matrix\:determinant\:according\:to\:formula}:\quad \det \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}\:=\:ad-bc

4\cdot \:6-3\cdot \:3=15

=\frac{1}{15}\begin{pmatrix}6&-3\\ -3&4\end{pmatrix}

=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}

Therefore, the inverse of given matrix is

=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}

4 0
3 years ago
A crew consists of 1 apprentice, 1 journeyman, and 1 master carpenter. The crew receives a check for $6400 for a job they just f
aleksklad [387]

Answer:

Apprentice = $800

Journeyman = $1600

carpenter = $4000

Step-by-step explanation:

Let the apprentice earns X dollars.

Then ,

Journeyman will make 200% of apprentice's earning which is 2X.

Also,

Carpenter makes 250% of the earning that journeyman makes.

Which is 2.5(2X) = 5X

Their total earning should come to $6400.

Thus,

X + 2X + 5X = 6400

8X = 6400.

X = $800

So,

Earning of apprentice = X = $800

Earning of Journeyman = 2X = $1600

Earning of carpenter = 5X = $4000

4 0
3 years ago
If g(x)= square root of 3-5x, find the domain of g'(x).
BaLLatris [955]

Answer:

domain: x>3/5

Step-by-step explanation:

First we need to derive our function g(x) to get a new function g'(x)

To do this we will have to apply chain rule because we have an inner and outer functions.

Our G(x) = square root(3-5x)

Chain rule formula states that: d/dx(g(f(x)) = g'(f(x))f'(x)

where d/dx(g(f(x)) = g'(x)

g(x) is the outer function which is x^1/2

f(x) is our inner function which is 3-5x

therefore f'(x)= 1/2x^(-1/2) and f'(x) = -5

g'(f(x)) = -1/2(3-5x)^(-1/2)

Applying chain rule then g'(x) = 1/2 (3-5x)^(-/1/2)*(-5)

But the domain is the values of x where the function g'(x) is not defined

In this case it will be 3-5x > 0, because 3-5x is a denominator and anything divide by zero is infinity/undefined

which gives us x >3/5

5 0
3 years ago
Read 2 more answers
PLEASE HELP!! if sec x=5/3 what is the value of b? NL=20 LM=3b angle of L is x degrees.
Readme [11.4K]

Answer:

a. b=4

Step-by-step explanation:

\sec \theta =\dfrac{1}{\cos \theta} = \dfrac{Hypotenuse}{Adjacent}

From the attached triangle drawn below:

NL=20,  LM=3b, \angle L=x^\circ

\sec x =\dfrac{20}{3b}

Since we are told that:

\sec x =\dfrac{5}{3}\\$Then:\\\dfrac{20}{3b} =\dfrac{5}{3}\\$Cross multiply\\5 \times 3b =20 \times 3\\15b=60\\$Divide both sides by 15\\15b \div 15 =60 \div 15\\b=4

The correct option is A.

8 0
3 years ago
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