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Fittoniya [83]
3 years ago
6

F = 9/5C + 32 solve for f​

Mathematics
1 answer:
grin007 [14]3 years ago
4 0

Answer:

substitute the value for C

Step-by-step explanation:

with that you'd be able to solve for x

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ALGEBRA Find mZA in ABC if mZB = 38º and mZC = 38º.
ValentinkaMS [17]

Answer:

d

Step-by-step explanation:

dddddddddddddddddddddddddddd

6 0
3 years ago
Plss it due today plssss don’t just take the points
Murljashka [212]

Answer:

Step-by-step explanation:

3x + 11 + x - 9 + 56 = 180

4x + 58 = 180

4x = 122

x = 30.5

6 0
3 years ago
During the final 5 seconds of a race a cyclist increased her velocity from 4 m/s to 7 m/s . What was her average acceleration du
GREYUIT [131]

Answer:

The average acceleration of the cyclist was 0.6 m/s².

Step-by-step explanation:

Acceleration:

The rate change of velocity per unit time is call the acceleration of the object.

a=\frac{v-u}t

u= initial velocity

v= final velocity

t= time taken change of velocity.

During the final 5 seconds of a race cyclist increased her velocity from 4m/s to 7 m/s

Here v= 7 m/s and u=4 m/s t=5 seconds

\therefore a=\frac{7\ m/s-4 \ m/s}{5s}

     =\frac{3}{5} \ m/s^2

     =0.6 m/s²

The average acceleration of the cyclist was 0.6 m/s².

8 0
3 years ago
The ratio of the number of gallons of gasoline a car uses to the number of miles it travels is 15: 330. In miles per gallon (mpg
Murrr4er [49]

Answer:22mpg

Step-by-step explanation:

330miles/15gallons per mile = 22 mpg

3 0
3 years ago
Read 2 more answers
What is the true solution to 3 In 2+In 8 = 2 In(4x)?<br> 60f<br> Š O OOO<br> TNT 00
alina1380 [7]

Answer:

  x = 2

Step-by-step explanation:

Taking antilogs, you have ...

  2³ × 8 = (4x)²

  64 = 16x²

  x = √(64/16) = √4

  x = 2 . . . . . . . . (the negative square root is not a solution)

___

You can also work more directly with the logs, if you like.

  3·ln(2) +ln(2³) = 2ln(2²x) . . . . . . . . . . . write 4 and 8 as powers of 2

  3·ln(2) +3·ln(2) = 2(2·ln(2) +ln(x)) . . . . use rules of logs to move exponents

  6·ln(2) = 4·ln(2) +2·ln(x) . . . . . . . . . . . . simplify

  2·ln(2) = 2·ln(x) . . . . . . . . . . . subtract 4ln(2)

  ln(2) = ln(x) . . . . . . . . . . . . . . divide by 2

  2 = x . . . . . . . . . . . . . . . . . . . take the antilogs

4 0
3 years ago
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