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vladimir1956 [14]
3 years ago
11

Solve for X in the figure below. Show your work. 22* Degrees 3x+11

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
7 0
Where’s the photo to this question?
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20 people applied for a job. Everyone either has a school certificate or diploma or even both. If 14 have school certificates an
STatiana [176]

Given:

Either has a school certificate or diploma or even both = 20 people

Having school certificates = 14

Having diplomas = 11

To find:

The number of people who have a school certificate only.

Solution:

Let A be the set of people who have school certificates and B be the set of people who have diplomas.

According to the given information, we have

n(A)=14

n(B)=11

n(A\cup B)=20

We know that,

n(A\cup B)=n(A)+n(B)-n(A\cap B)

20=14+11-n(A\cap B)

20=25-n(A\cap B)

Subtract both sides by 25.

20-25=-n(A\cap B)

-5=-n(A\cap B)

5=n(A\cap B)

We need to find the number of people who have a school certificate only, i.e. n(A\cap B').

n(A\cap B')=n(A)-n(A\cap B)

n(A\cap B')=14-5

n(A\cap B')=9

Therefore, 9 people have a school certificate only.

3 0
3 years ago
What is 8.362 rounded to the nearest hundredth?
Aleksandr [31]

Answer:8.300

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Y=-x^2+2x+10<br> y=x+2<br><br> Substitution <br> Please show your work<br> Need ASAP
erik [133]

Answer:

The solutions of the system of equations are the points

(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})  

(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})  

Step-by-step explanation:

we have

y=-x^{2} +2x+10 ----> equation A

y=x+2 ----> equation B

Solve the system by substitution

substitute equation B in equation A

x+2=-x^{2} +2x+10

solve for x

-x^{2} +2x+10-x-2=0

-x^{2} +x+8=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-x^{2} +x+8=0

so

a=-1\\b=1\\c=8

substitute in the formula

x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}

x=\frac{-1\pm\sqrt{33}} {-2}

x=\frac{-1+\sqrt{33}} {-2}  -----> x=\frac{1-\sqrt{33}} {2}  

x=\frac{-1-\sqrt{33}} {-2}  -----> x=\frac{1+\sqrt{33}} {2}  

<em>Find the values of y</em>

For x=\frac{1-\sqrt{33}} {2}  

y=x+2

y=\frac{1-\sqrt{33}} {2}+2  ---->y=\frac{5-\sqrt{33}} {2}  

For x=\frac{1+\sqrt{33}} {2}  

y=x+2

y=\frac{1+\sqrt{33}} {2}+2  ---->y=\frac{5+\sqrt{33}} {2}  

therefore

The solutions of the system of equations are the points

(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})  

(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})  

5 0
3 years ago
A boat travels 36 miles in 1.5 hours ans then in 14 miles in 0.75 hour. what is the average speed?
allochka39001 [22]

The average speed can be obtained by the formula:

V_{\text{average}}=\dfrac{\text{total distance}}{\text{total time}}.

If a boat travels 36 miles in 1.5 hours ans then in 14 miles in 0.75 hour, then find:

  • total distance is 36+14=50 miles;
  • total time: 1.5+0.75=2.25 hours.

Therefore,

V_{\text{average}}=\dfrac{50}{2.25}=\dfrac{5000}{225}=\dfrac{200}{9}=22.(2) miles per hour.

Answer: V_{\text{average}}=\dfrac{200}{9}=22.(2) miles per hour.

6 0
3 years ago
Read 2 more answers
Find the common factor and factor out <br> 9ab^2-3abc
dsp73
Lets go step by step and factor out each as we go

first lets factor out a 3 since 3 is common in 9 and 3 

3(3ab^2 - abc) 

now lets factor out a since its common in both 

3a(3b^2 - bc) 

now lets factor out a b since its common in both 

3ab(b - c) 

we can't factor anything else out so we are done. 

4 0
3 years ago
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