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vladimir1956 [14]

3 years ago

11

Solve for X in the figure below. Show your work. 22* Degrees 3x+11

1 answer:

Snowcat [4.5K]3 years ago

7 0

Where’s the photo to this question?

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20 people applied for a job. Everyone either has a school certificate or diploma or even both. If 14 have school certificates an

STatiana [176]

Given:

Either has a school certificate or diploma or even both = 20 people

Having school certificates = 14

Having diplomas = 11

To find:

The number of people who have a school certificate only.

Solution:

Let A be the set of people who have school certificates and B be the set of people who have diplomas.

According to the given information, we have

$n(A)=14$

$n(B)=11$

$n(A\cup B)=20$

We know that,

$n(A\cup B)=n(A)+n(B)-n(A\cap B)$

$20=14+11-n(A\cap B)$

$20=25-n(A\cap B)$

Subtract both sides by 25.

$20-25=-n(A\cap B)$

$-5=-n(A\cap B)$

$5=n(A\cap B)$

We need to find the number of people who have a school certificate only, i.e. $n(A\cap B')$ .

$n(A\cap B')=n(A)-n(A\cap B)$

$n(A\cap B')=14-5$

$n(A\cap B')=9$

Therefore, 9 people have a school certificate only.

3 0

3 years ago

What is 8.362 rounded to the nearest hundredth?

Aleksandr [31]

Answer:8.300

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Y=-x^2+2x+10<br> y=x+2<br><br> Substitution <br> Please show your work<br> Need ASAP

erik [133]

Answer:

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

Step-by-step explanation:

we have

$y=-x^{2} +2x+10$ ----> equation A

$y=x+2$ ----> equation B

Solve the system by substitution

substitute equation B in equation A

$x+2=-x^{2} +2x+10$

solve for x

$-x^{2} +2x+10-x-2=0$

$-x^{2} +x+8=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-x^{2} +x+8=0$

so

$a=-1\\b=1\\c=8$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}$

$x=\frac{-1\pm\sqrt{33}} {-2}$

$x=\frac{-1+\sqrt{33}} {-2}$ -----> $x=\frac{1-\sqrt{33}} {2}$

$x=\frac{-1-\sqrt{33}} {-2}$ -----> $x=\frac{1+\sqrt{33}} {2}$

<em>Find the values of y</em>

For $x=\frac{1-\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1-\sqrt{33}} {2}+2$ ----> $y=\frac{5-\sqrt{33}} {2}$

For $x=\frac{1+\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1+\sqrt{33}} {2}+2$ ----> $y=\frac{5+\sqrt{33}} {2}$

therefore

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

5 0

3 years ago

A boat travels 36 miles in 1.5 hours ans then in 14 miles in 0.75 hour. what is the average speed?

allochka39001 [22]

The average speed can be obtained by the formula:

$V_{\text{average}}=\dfrac{\text{total distance}}{\text{total time}}.$

If a boat travels 36 miles in 1.5 hours ans then in 14 miles in 0.75 hour, then find:

total distance is 36+14=50 miles;
total time: 1.5+0.75=2.25 hours.

Therefore,

$V_{\text{average}}=\dfrac{50}{2.25}=\dfrac{5000}{225}=\dfrac{200}{9}=22.(2)$ miles per hour.

Answer: $V_{\text{average}}=\dfrac{200}{9}=22.(2)$ miles per hour.

6 0

3 years ago

Read 2 more answers

Find the common factor and factor out <br> 9ab^2-3abc

dsp73

Lets go step by step and factor out each as we go

first lets factor out a 3 since 3 is common in 9 and 3

3(3ab^2 - abc)

now lets factor out a since its common in both

3a(3b^2 - bc)

now lets factor out a b since its common in both

3ab(b - c)

we can't factor anything else out so we are done.

4 0

3 years ago