Answer:
Area of Trapezoid is 39 unit²
Step-by-step explanation:
Given as :
For A Trapezoid
The measure of base side 1 =
= 10 unit
The measure of base side 2 =
= 16 unit
The height of the Trapezoid = h = 3 unit
Let The Area of Trapezoid = A square unit
<u>Now, From Formula</u>
Area of Trapezoid =
× (sum of opposite base) × height
I.e A =
× (
+
) × h
Or, A =
× (10 unit + 16 unit) × 3 unit
Or, A =
× (26 unit) × 3 unit
Or, A =
× 78 unit²
Or, A =
unit²
I.e A = 39 unit²
So, The Area of Trapezoid = A = 39 unit²
Hence, The Area of Trapezoid is 39 unit² . Answer
Answer:
f(x) = -4x + 20
Refer attachment for graph.
Step-by-step explanation:
Given: when Zane was 20 meters below the edge of a volcano. He heard some rumbling, so he decided to climb up out of there as quickly as he could. He managed to climb up 4 meters each second and get out of the volcano safely.
We have to graph Zane's elevation relative to the edge of the volcano (in meters) as a function of time (in seconds).
Let he takes x seconds to get out of the volcano.
and y be the distance covered by the volcano to reach Zane.
Then, to reach the edge of volcano,
Thus, The equation that represent Zane's elevation relative to the edge of the volcano (in meters) as a function of time (in seconds). is given by
f(x) = -4x + 20
At x = 0 the Zane will be at f(0) = 20 that is 20 meter below the volcano.
Thus points are (0,20)
and when x = 5 Zane will be escaped from volcano.
Thus points are (5,0)
Plot this and obtained the graph for the given equation as attached below.
10%
200 x x%=20
x=10%
Do u understand ?
Answer:
8 seconds.
Step-by-step explanation:
To solve this question, we need to find the time,
, when
, that is, when the height of the object above the ground is 0 feet.
Substituting
feet per second and
gives the quadratic:

Since 128 is divisible by 16, it can be reduced to
.
We must now solve for
.
We can easily see that one answer to the equation is 0,
(we need not concern ourselves with the 16 outside of the parenthesis as in the equation above, since 16 multiplied by 0 is 0). However this is the time the object is released into the air.
The second answer,
is also easy to see by inspection:
.
Therefore the object lands 8 seconds after it is thrown.
Answer:
0.8745.
Step-by-step explanation:
P(success) = 0.09 and P(failure) = 1 - 0.09 = 0.91.
P( at least 6 failures) = P( less than 2 successes)
= 7C0 (0.09)^0 (0.91)^7 + 7C1 (0.09)(0.91)^6
= 0.5168 + 0.3577
= 0.8745.