Answer:
Positive angles located in the fourth quadrant may be described as<u> 270≤Ф≤360
.</u>
The option is
4. 270≤Ф≤360
Step-by-step explanation:
When the terminal arm of an angle starts from the x-axis in the anticlockwise direction then the angles are always positive angles.
For Example.
Quadrant I - 0 to 90°
Quadrant II - 90° to 180°
Quadrant III - 180° to 270°
Quadrant IV - 270° to 360° ( 4. 270≤Ф≤360 )
Hence,Positive angles located in the fourth quadrant may be described as<u> 270≤Ф≤360
.</u>
When the terminal arm of an angle starts from the x-axis in the clockwise direction than the angles are negative angles.
Quadrant IV - 0° to -90°
Quadrant III - - 90° to -180°
Quadrant II - -180° to -270°
Quadrant I - -270° to -360°
X^1/2 or x to the 1/2 power
Answer:
y-5 = 3/2(x-3)
Step-by-step explanation:
The point slope form of the equation of a line is
y-y1 = m(x-x1) where m is the slope and (x1,y1) is a point on the line
y-5 = 3/2(x-3)
The slope is 3/1
hope this helps
Answer:
50 cupcakes, 150 cookies
Step-by-step explanation:
