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3 years ago

Alfred made 21 goals in 3.5 minutes. What is alfreds unit rate?

Mathematics

1 answer:

Readme [11.4K]3 years ago

4 0

Answer:

Alfred’s unit rate is 6 goals per minutes.

Step-by-step explanation:

To get the unit rate just divide 21 by 3.5

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Explain how you can find the amount of money Juan save if he earned $12 walking dogs

Lisa [10]

You can find how many he gets for each dog.

For example, let's pretend Juan gets $3 for each dog to walk, then he would've walked 4 dogs. But in this real problem we don't know how much he gets for each dog.

So, you can find the amount of money Juan saved by knowing how much is for each dog walked.

6 0

3 years ago

Drinks cost 85p each.

bagirrra123 [75]

11 drinks because 85x11 = £9.35

7 0

2 years ago

Plsss help meee in math :(((

pishuonlain [190]

Answer:

a = 30

2a = 60

3a = 90

Step-by-step explanation:

3a + 2a + a = 180 ( Sum of angles of a triangle is 180)

6a = 180

a = 180/6

a = 30

2a = 2 x 30 =60

3a = 3 x 30 = 90

6 0

2 years ago

A plant grows inch every month. How many inches does the plant grow in 10 months?

Lerok [7]

Answer:

10 inches

Step-by-step explanation:

Ummm 1 · 10 = 10

3 0

2 years ago

Read 2 more answers

The production department of Celltronics International wants to explore the relationship between the number of employees who ass

Flura [38]

Answer:

(a) Shown below

(b) There is a positive relation between the number of assemblers and production.

Step-by-step explanation:

Let X = number of assemblers and Y = number of units produced in an hour.

(a)

Consider the scatter plot below.

(b)

Based on the scatter plot it can be concluded that there is a positive relationship between the variables X and Y, i.e. as the value of X increases Y also increases.

(c)

The formula to compute the correlation coefficient is:

$r=\frac{n\sum XY-\sum X\sum Y}{\sqrt{[n\sum X^{2}-(\sum X)^{2}][n\sum Y^{2}-(\sum Y)^{2}]}} }$

Compute the correlation coefficient between X and Y as follows:

$r=\frac{n\sum XY-\sum X\sum Y}{\sqrt{[n\sum X^{2}-(\sum X)^{2}][n\sum Y^{2}-(\sum Y)^{2}]}} }=\frac{(5\times430)-(15\times120)}{\sqrt{[(5\times55)-15^{2}][(5\times3450)-120^{2}]}} =0.9272$

Thus, the correlation coefficient is 0.9272.

7 0

2 years ago