Answer:
8a. x = 16√3
8b. y = 8√3
Step-by-step explanation:
8a. Determination of the value of x
Adjacent = 24
Hypothenus = x
Angle θ = 30°
The value of x can be obtained by using cosine ratio as illustrated below:
Cos θ = Adjacent /Hypothenus
Cos 30 = 24 / x
√3/2 = 24/x
Cross multiply
x × √3 = 2× 24
x × √3 = 48
Divide both side by √3
x = 48/√3
Rationalise
x = 48/√3 × √3/√3
x = 48√3 / √3 × √3
x = 48√3 / 3
x = 16√3
8b. Determination of the value of y
Opposite = y
Adjacent = 24
Angle θ = 30°
The value of y can be obtained by using Tan ratio as illustrated below:
Tan θ = Opposite / Adjacent
Tan 30 = y / 24
1 / √3 = y /24
Cross multiply
y × √3 = 1 × 24
y × √3 = 24
Divide both side by √3
y = 24 /√3
Rationalise
y = 24 /√3 × √3/√3
y = 24 ×√3 / √3 × √3
y = 24√3 / 3
y = 8√3
The answer is True.
Since we are talking about the cost of something, and whenever you have a y-intercept, it means the price.
The y-intercept represents the initial cost of the taxi ride then how many miles you ride for, the more you pay plus the initial cost.
Best of Luck!
Answer:
Y=-5/3x-1
y=2/3x-8
If you are adding then it is:
7x=21
x=3
Step-by-step explanation:
5x+3y=-3
3y=-5x-3
y=-5/3-1
2x-3y=24
-3y=-2x+24
y=2/3x-8
Question:
A cinema can hold 270 people at one performance 5/9 of the seats were occupied of the occupied seats 40% we occupied by concessionary ticket holders.
What is the number of seats occupied by concessionary ticket holders?.
Answer:
60 seats
Step-by-step explanation:
Given
Number of seats = 270
Occupied Seats = 5/9
Concessionary ticket holders = 40% of occupied Seats
Required
The number of seats occupied by concessionary ticket holders
First the number of occupied seat has to be calculated.
Next is to determine the number of seats occupied by concessionary ticket holders.
Convert percentage to decimal
<em>Hence, 60 seats were occupied by concessionary ticket holders.</em>
Answer:
The cross section would be a square.
Step-by-step explanation:
The 2 ends of the rectangular prism are squares while the other 4 sides are rectangles. A cross section would be perpendicular to the rectangles, making the cross section a square. The cross section would be parallel to the end squares.
