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jarptica [38.1K]
3 years ago
9

What are the outputs and inputs of y=-3x+5

Mathematics
1 answer:
Simora [160]3 years ago
3 0

Answer:

-by-step explanation:Step

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SOMEONE PLEASE HELP!!
german

-12=\dfrac{-12}{1}=\dfrac{12}{-1}=\dfrac{-24}{2}=\dfrac{24}{-2}=\dfrac{-36}{3}=\dfrac{36}{-3}=\dfrac{-48}{4}=\dfrac{48}{-4}=\dots

7 0
3 years ago
I need plz help fast
Bad White [126]

Answer:

<h2>-4a²b³ (-6+ 7a³)</h2><h2 />

Step-by-step explanation:

24a²b³ - 28a⁵b³

apply exponential rule:

24a²b³ - 28a²a³b³

re-write 24 as 6*4    and  -28 as 7*4

6*4a²b³ + 7*4a²a³b³

factor common terms

-4a²b³ (-6+ 7a³)

3 0
3 years ago
The black dot inside this circle is its
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Answer:

d i believe b is your answer your welcome

6 0
3 years ago
Read 2 more answers
5/3 (2+x) = 4/5(x+1/2) + 1/3
Goshia [24]

Answer: x= -3

Step-by-step explanation:

6 0
3 years ago
Me. Ellis is a teacher who tutors after school. Of the students he tutors, 30% need help in computer science and 70% need assist
Anna11 [10]

Answer: There are 82.5% after school students who are enrolled in his classes.

Step-by-step explanation:

Let the total number of students be 100

Percentage of students who need help in computer science = 30%

So, number of students who need help in computer science = 30

Percentage of students who need help in maths = 70%

So, number of students who need assistance in maths  = 70

Of the students who need help,

40% are enrolled in Mr. Ellis's class during the school day,

So, it means 60% are enrolled in his class after the school day.

Number of students who are enrolled in his class after the school day = 60

Number of students who need help in Maths is given by

\frac{70}{100}\times 60=42

Of the students that need help in maths, percent of students are enrolled in his class during the day = 25%

So, number of students who need help in maths and enrolled in his class after school hours

\frac{75}{100}\times 42=31.5

Number of students who need help in computer science and enrolled in his class after school hours

\frac{30}{100}\times 60=18

Therefore, there are 31.5+18=49.5 students who joined his class after school hours,

Percentage of the after students who are enrolled in Mr. Ellis's classes is given by

\frac{49.5}{60}\times 100=82.5\%

Hence, there are 82.5% after school students who are enrolled in his classes.


6 0
4 years ago
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