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DerKrebs [107]
3 years ago
10

ASAP! can someone help solve this with work?

Mathematics
1 answer:
KengaRu [80]3 years ago
7 0

Answer:

I don't just want to tell you the answer but I can tell you how.

Step-by-step explanation:

Use the pythagorean theorem, since this is a right triangle. If you don't know what this is its a^2+b^2=c^2

I hope this helps, if you have questions comment or look online.

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Brianna is constructing a raised flower bed in the shape of a rectangle. The length of the flower bed is equal to the width plus
inessss [21]
I think the answer is 5 feet because 2(2+5)= 4+10=14. So the missing length is 5 feet.
4 0
2 years ago
Please answer this correctly
FrozenT [24]
20 buttons in total
Because he has
5 white buttons
2 fewer brown
5-2 =3
So 3 brown
9 more gray than brown
3+9 = 12
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5+3+12=20
8 0
2 years ago
LXISSUU<br> Simplify<br> -8-1+4.2<br> Enter your answer in the box
jekas [21]

Answer:

-4.8

Step-by-step explanation:

4 0
3 years ago
David found and factored out the GCF of the polynomial 80b4 – 32b2c3 + 48b4c. His work is below. GFC of 80, 32, and 48: 16 GCF o
BlackZzzverrR [31]

Answer: The correct statements are

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

David applied the distributive property.

Step-by-step explanation:

GCF = Greatest common factor

1) GCF of coefficients : (80,32,48)

80 = 2 × 2 × 2 × 2 × 5

32 = 2 × 2 × 2 × 2 × 2

48 = 2 × 2 × 2 × 2 × 3

GCF of coefficients : (80,32,48) is 16.

2) GCF of variables :(b^4,b^2,b^4)

b^4= b × b × b × b

b^2 = b × b

b^4 =b × b × b × b

GCF of variables :(b^4,b^2,b^4) is b^2

3) GCF of c^3 and c: c is not the GCF of the polynomial. The variable c is not common to all terms, so a power of c should not have been factored out.

4) 80b^4-32b^2c^3+48b^4c

=16b^2(5b^2-2c^3+3b^2c)

David applied the distributive property.

7 0
2 years ago
Read 3 more answers
Simplify the expression: the square root of -13 times the square root of -26 calculator
Rasek [7]
Sqrt -13  = sqrt13 i
sqrt  -26  =  sqrt2 * sqrt13i 

sqrt-13 * sqrt -26  = sqrt2 * 13*  i^2  = -13 sqrt2 (because i^2 = -1)

answer is -13 sqrt2
6 0
3 years ago
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