Question

What is the slope of a line perpendicular to the line whose equation is y = 2x+5?

Answer 1

Answer:

Slope $m_{2} = \frac{-1}{2}$.

Step-by-step explanation:

Given  :  equation is y = 2x+5.

To find : What is the slope of a line perpendicular to the line.

Solution : We have given y = 2x+5.

On comparing by the slope form of line is

y = mx + b

where, m = slope , b = y-inercept.

So , $m_{1}$ = 2 .

When the two line are perpendicular to each other then thier slope is

$m_{2} = \frac{-1}{m_{1}}$.

Then plug the value of  $m_{1}$ = 2 .

$m_{2} = \frac{-1}{2}$.

$m_{2} = \frac{-1}{2}$.

Therefore, Slope $m_{2} = \frac{-1}{2}$.

Answer 2

Answer:

slope = - $\frac{1}{2}$

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 2x + 5 is in this form with slope m = 2

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{2}$