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Anna35 [415]
3 years ago
15

At president Bush's inauguration in 2005,the newspaper headlines stated there were about 400,00 people in attendance. if the new

spaper rounded to the nearest ten thousand, what is the largest number and smallest number of people that could have been there?
Mathematics
2 answers:
Stolb23 [73]3 years ago
5 0

Answer:

Largest : 404000

Smallest : 395000

Step-by-step explanation:

At president Bush's inauguration in 2005,the newspaper headlines stated there were about 400,000 people in attendance.

As the newspaper rounded to the nearest ten thousand , so the largest number of people will be = 404000  (if it were 405000, it will round to 410000 which is wrong)

The smallest number or people will be = 395000

Crazy boy [7]3 years ago
3 0
The smallest would have been 35,000.  The largest would have been 44,999.
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Gemiola [76]

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Step-by-step explanation:

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7 0
3 years ago
Solve: -4.878-(-8.96)=
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7 0
3 years ago
Read 2 more answers
I hope it’s clear enough but can some please help
Liula [17]

Answer:

b

Step-by-step explanation:

hope this helps you! have a good day!

6 0
3 years ago
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iVinArrow [24]
 3x+7 = 51-x
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4 0
3 years ago
PLEASE:
Tju [1.3M]

Answer:

63.59 in²

Step-by-step explanation:

The formula to find the area of a square: a², where a is the side.

The formula to find the area of a circle: πr², where r is the radius (diameter ÷ 2), and the pi is alterable (3.14 or 3.142 or 22/7).

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a²

a = √81

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3) Round off the result to the nearest hundredth.

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3 0
2 years ago
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