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makkiz [27]
3 years ago
11

What is 12/21 divided by 3/14

Mathematics
1 answer:
sladkih [1.3K]3 years ago
5 0
To do this problem, you gotta cross-multiply. SO, \frac{12}{21} multiplied by \frac{14}{3}

12 times 14 = 168
21 times 3 = 63
Then the final answer is \frac{168}{3}
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In the spinner below, what is true about the probability of landing on 1 and the probability of landing on 6?​
Tanzania [10]

Answer:

1/6 for 1 and 1/6 for 6

Step-by-step explanation:

4 0
3 years ago
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Just this one
S_A_V [24]

Answer:

15%

Step-by-step explanation:

900/6000

which is the same as 900÷6000

900÷6000= 0.15

0.15 as a percent in 15%

7 0
2 years ago
The value of the solid's surface area is equal to the value of the solid's volume. find the value of x. 5*6*x
velikii [3]
<h3>Given</h3>

a cuboid with length, width, height dimensions 5, 6, x

<h3>Find</h3>

the value of x that makes the numerical value of the total surface area equal to the numerical value of the volume

<h3>Solution</h3>

The volume is given by

... V = L·W·H = 5·6·x = 30x

The area is given by

... A = 2(L·W + H(L+W)) = 2(5·6 +x(5+6)) = 2(30 +11x) = 60 +22x

When these are equal, we have

... 30x = 60 +22x

... 8x = 60

... x = 7.5

The desired value of x is 7.5.

7 0
3 years ago
A prize is divided in the ratio 5:1 if the larger share is £65 what is the total prize?
Paha777 [63]

Answer:

£78

Step-by-step explanation:

65 divided by 5= £13

13+65=£78

6 0
2 years ago
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A probability experiment is conducted in which the sample space of the experiment is upper s equals startset 4 comma 5 comma 6 c
olchik [2.2K]
The correct question statement is:

A probability experiment is conducted in which the sample space of the experiment is S = {4,5,6,7,8,9,10,11,12,13,14,15}. Let event E={7,8,9,10,11,12,13,14,15}. Assume each outcome is equally likely. List the outcomes in E^{c}. Find P(E^{c}).

Solution:

Part 1:

E^{c} means compliment of the set E. A compliment of a set can be obtained by finding the difference of the set from the universal set. The universal set is the set which contains all the possible outcomes of the events which is S in this case.

So, compliment of E will be equal to S - E. S - E will result in all those elements of S which are not present in E. So, we can write:

E^{c}=S-E \\  \\ &#10;E^{c}=(4,5,6,7,8,9,10,11,12,13,14,15)-(7,8,9,10,11,12,13,14,15) \\  \\ &#10;E^{c}=(4,5,6)

Thus the set compliment of E will contain the elements {4,5,6}.So

E^{c} = {4,5,6}

Part 2)

P(E^{c}) means probability that if we select any number from the Sample Space S, it will belong the set E compliment.

P(E^{c}) = (Number of Elements in E^{c})/Number of elements in S

Number of elements in set S = n(S) = 12
Number of elements in set E^{c} = n(E^{c})=3

So, 

P(E^{c})= \frac{n(E^{c}) }{n(S)} \\  \\ &#10;P(E^{c})= \frac{3}{12} \\  \\ &#10;P(E^{c})= \frac{1}{4}
7 0
3 years ago
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