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3 years ago

A kangaroo hops 2 kilometers in 5 minutes at this rate how far does the kangaroo travel in 2 minutes

Mathematics

1 answer:

nlexa [21]3 years ago

8 0

Answer:

1.3 kilometers

Step-by-step explanation:

It is given,

A kangaroo hops 2 kilometers in 3 minutes.

I.e. In 3 minutes, a kangaroo hops 2 kilometers.

Thus, in 2 minutes, it will hop kilometers

i.e. It will hop kilometers

i.e. It will hop 1.3 kilometers

Hence, in 2 minutes the kangaroo will hop 1.3 kilometers.

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Find the area of the composite figure.

Roman55 [17]

Answer:

The Area of the composite figure would be 76.26 in^2

Step-by-step explanation:

According to the Figure Given:

Total Horizontal Distance = 14 in

Length = 6 in

To Find :

The Area of the composite figure

Solution:

Firstly we need to find the area of Rectangular part.

So We know that,

$\boxed{ \rm \: Area \: of \: Rectangle = Length×Breadth}$

Here, Length is 6 in but the breadth is unknown.

To Find out the breadth, we’ll use this formula:

$\boxed{\rm \: Breadth = total \: distance - Radius}$

According to the Figure, we can see one side of a rectangle and radius of the circle are common, hence,

$\longrightarrow\rm \: Length \: of \: the \: circle = Radius$

Since Length = 6 in ;

$\longrightarrow \rm \: 6 \: in = radius$

Hence Radius is 6 in.

So Substitute the value of Total distance and Radius:

Total Horizontal Distance= 14
Radius = 6

$\longrightarrow\rm \: Breadth = 14-6$

$\longrightarrow\rm \: Breadth = 8 \: in$

Hence, the Breadth is 8 in.

Then, Substitute the values of Length and Breadth in the formula of Rectangle :

Length = 6
Breadth = 8

$\longrightarrow\rm \: Area \: of \: Rectangle = 6 \times 8$

$\longrightarrow \rm \: Area \: of \: Rectangle = 48 \: in {}^{2}$

Then, We need to find the area of Quarter circle :

We know that,

$\boxed{\rm Area_{(Quarter \; Circle) } = \cfrac{\pi{r} {}^{2} }{4}}$

Now Substitute their values:

r = radius = 6
π = 3.14

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times 6 {}^{2} }{4}$

Solve it.

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times 36}{4}$

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times \cancel{{36} } \: ^{9} }{ \cancel4}$

$\longrightarrow\rm Area_{(Quarter \; Circle)} =3.14 \times 9$

$\longrightarrow\rm Area_{(Quarter \; Circle) } = 28.26 \: {in}^{2}$

Now we can Find out the total Area of composite figure:

We know that,

$\boxed{ \rm \: Area_{(Composite Figure)} =Area_{(rectangle)}+ Area_{ (Quarter Circle)}}$

So Substitute their values:

$\rm Area_{(rectangle)}$ = 48
$\rm Area_{(Quarter Circle)}$ = 28.26

$\longrightarrow \rm \: Area_{(Composite Figure)} =48 + 28 .26$

Solve it.

$\longrightarrow \rm \: Area_{(Composite Figure)} =\boxed{\tt 76.26 \:\rm in {}^{2}}$

Hence, the area of the composite figure would be 76.26 in² or 76.26 sq. in.

$\rule{225pt}{2pt}$

I hope this helps!

3 0

2 years ago

(7x+5)/(6) write the fraction as a sum or difference

Digiron [165]

Answer: Factor the numerator and denominator and cancel the common factors.

7x/6+5/6

Step-by-step explanation:

8 0

3 years ago

What is the decimal equivalent for 5/8 7/10 11/20 and 21/25? And please explain how you got the answer for 21/25 without using a

Svetllana [295]

5/8 multiply with 125/125 = 625/1000 -> 0.625
7/10 -> 0.7
11/20 multiply with 5/5 = 55/100 -> 0.55
21/25 multiply with 4/4 = 84/100 -> 0.84

3 0

3 years ago

Can someone help with this please??

finlep [7]

4, 5 & 6 were answered on another question plus the circle isn't shown on this one.

7. semi circle is half a circle, there re 4 arcs smaller then half
they are DB, DC, AC and AB

last choice is correct

4 0

3 years ago

What is the 12th term of the sequence 3,6,12,24....

Sati [7]

$a_{0}$ =3

r=common ratio: 12/6=2; 6/3=2

r=2, $a_{n}$ = $2^{n-1}$ *3

plug in 12 for n:

$a_{12}$ = $2^{12-1}$ *3

$a_{12}$ = $2^{11}$ *3

$a_{12}$ =2048*3

$a_{12}$ =6144

The twelfth term in the sequence is 6144

7 0

4 years ago

Read 2 more answers