Answer:
:5:5&&'4&4&4&:&;4"33*2**223$&4&4&55&
When you have this type of problem, you need to combine the like-terms and isolate the variable.
3x + 122 = 22x - 11
Add 11 to both sides to get rid of it
3x + 122 + 11 = 22x - 11 + 11 (-11 + 11=0)
3x + 133 = 22x
Then you would bring the 3x to the other side, so subtract 3x from both sides
3x + 133 = 22x
-3x -3x
133 = 22x - 3x
133 = 19x
Then divide both sides by 19 to isolate x
133/19 = 19x/19
133/19 = 7, so x = 7
Hope this helps!!
40,000 is your answer hope I could help
Answer:
19 - (6/5)j
Step-by-step explanation:
In this expression we have addition, subtraction and multiplication.
According to order of operations rules, mult. and div. must be carried out before add. or subt.
Therefore, we begin with 17+(-4), which becomes 17 - 4, or 13.
Next we see -4/5j, by which I assume you mean -4/5 * j.
Summarizing what we have so far:
13 - (4/5)j - 2/5j + 6
Combining the j terms, we get
13 - (6/5)j + 6, which collapses to 19 - (6/5)j.
Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
