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3 years ago

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For which conditions is p v q false? (A) p is true and q is false (B) P is true and q is true. (C) p is false and q is false (D)

p is false and q is false

1 answer:

viva [34]3 years ago

4 0

The answer to this question is C.
<span>When P is false and Q is false the P v Q is false</span>

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4 7/12 + 2 1/12 what is the estimate answer

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$4 \frac{7}{12} = \frac{12*4+7}{12} = \frac{55}{12} \\ \\ 2 \frac{1}{12} = \frac{2*12+1}{12} = \frac{25}{12} \\ \\ \frac{55}{12} + \frac{25}{12} = \frac{80}{12} \\ \\ \frac{80 :4}{4:4} = \frac{20}{3}$

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What's 57/100 + 3/10

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Answer:

Step-by-step explanation:

57/100 + 3/10

they need common denominators so a common denominator is 100

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Carina begins to solve the equation -4 - 2/3x = -6 by adding 4 to both sides. Which statements regarding the rest of the solving

Andru [333]

Answer:

A.) After adding 4 to both sides, the equation is $-\frac{2}{3}x=-2$

C.) The equation can be solved for x using exactly one more step by multiplying both sides by $-\frac{3}{2}$

D.) The equation can be solved for x using exactly one more step by dividing both sides by $-\frac{2}{3}$

Step-by-step explanation:

The correct questions is as follows:

Carina begins to solve the equation -4-2/3x=-6 by adding 4 to both sides. Which statements regarding the rest of the solving process could be true? Check all that apply.

A.) After adding 4 to both sides, the equation is -2/3x=-2.

B.) After adding 4 to both sides, the equation is -2/3x=-10 .

C.) The equation can be solved for x using exactly one more step by multiplying both sides by -3/2.

D.) The equation can be solved for x using exactly one more step by dividing both sides by -2/3.

E.) The equation can be solved for x using exactly one more step by multiplying both sides by -2/3.

Given equation:

$-4-\frac{2}{3}x=-6$

To show the steps we will carry out in order to solve for $x$

Solution:

Solving for $x$

Step 1:

Adding both sides by 4

$4-4-\frac{2}{3}x=-6+4$

Thus, we get:

$-\frac{2}{3}x=-2$

Thus statement A is correct.

Step 2:

Multiplying both sides by $-\frac{3}{2}$

$-\frac{3}{2}\times -\frac{2}{3}x=-2\times -\frac{3}{2}$

Thus, we get:

$x=3$ [Two negatives multiply to give a positive]

This proves that statement C is correct.

Or Step 2:

Dividing both sides by $-\frac{2}{3}$

$\frac{-\frac{2}{3}x}{-\frac{2}{3}}=\frac{-2}{-\frac{2}{3}}$

Thus, we get:

$x=-2\times -\frac{3}{2}$ [On dividing with a fractional divisor, we take reciprocal and multiply it with the dividend.]

$x=3$ [Two negatives multiply to give a positive]

This prove that statement D is correct.

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3 years ago

Find the equation of the line passing through the point (6,3) that is perpendicular to the line 4x−5y=−10.

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Step-by-step explanation:

( y = 4x/5 + 2)

m1.m2 = -1

4/5.m2 = -1

m2 = -5/4

formula = y - y1 = m2 ( x - x1)

y - 3 = -5/4 ( x - 6)

y -3 = -5x /4 + 30/4

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Answer:

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Step-by-step explanation:

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