Let a =70° and b= 10° (and a-b=70-10 =60)
We have the following trigonometric identity:
sin(a-b) = sin(a).cos(b)-sin(b).cos(a) OR:
sin(70-10) = sin70.cos10 - sin10.cos70
But sin(70-10) = sin(60) and we know that sin(60°) =(√3)/2
Answer:
a) The test is left-tailed.
Step-by-step explanation:
a) Hypothesis testing is tagged two-tailled if the test checks for a claim in both directions (greater than and less than).
It is one tailed if it checks for a claim in only one direction (either greater than or less than). It is left-tailed of it is testing the claim in a less than direction and right-tailed if it is testing the claim in a greater than direction.
This question is to check results from a test of the claim that less than 8% of treated subjects experienced headaches. It is evidently left tailed.
Hope this Helps!!!
Answer:
AC+ CD = ACD
X+1 + 2X + 2 = 30
3X+3 =30
3X=30–3
3X=27
X= 27/ 3
X= 9
I'm not sure of the solution, but I solved it according to a straight line (Line segment) .
I hope I helped you^_^
7.25$ for one box of paper
Explanation: divide 14.50 by 2
