Answer:
•A c-chart is the appropriate control chart
• c' = 8.5
• Control limits, CL = 8.5
Lower control limits, LCL = 0
Upper control limits, UCL = 17.25
Step-by-step explanation:
A c chart is a quality control chart used for the number of flaws per unit.
Given:
Past inspection data:
Number of units= 100
Total flaws = 850
We now have:
c' = 850/100
= 8.5
Where CL = c' = 8.5
For control limits, we have:
CL = c'
UCL = c' + 3√c'
LCL = c' - 3√c'
The CL stands for the normal control limit, while the UCL and LCL are the upper and lower control limits respectively
Calculating the various control limits we have:
CL = c'
CL = 8.5
UCL = 8.5 + 3√8.5
= 17.25
LCL = 8.5 - 3√8.5
= -0.25
A negative LCL tend to be 0. Therefore,
LCL = 0
Answer:
v = 220 yd²
Step-by-step explanation:
Small portion
v = 5 * 4 * 3
v = 60 yd²
Large portion
v = 9 * 6 * 3
v = 162 yd²
Total
v = 60 + 162
v = 220 yd²
Answer: Subtract 3 from each side of the equation(A)
Step-by-step explanation:
3n2−15n=3
1:Subtract 3n2 from both sides.
-15n=3-3n2
2:Divide both sides by -15.
-15n/-15=3-3n2/-15
3:Dividing by −15 undoes the multiplication by −15.
n=3-3n2/-15
4:Divide 3−3n 2 by −15
n=n2-1/5
The answer is cot² ∅ - csc² ∅ = -1
Referring to Pythagorean identities:
sin² ∅ + cos² ∅ = 1
1+cot² ∅ = csc² ∅
tan² ∅ + 1 = sec² ∅
1+cot² ∅ = csc² ∅
⇒ transposing 1 and csc² ∅ we will have now
cot² ∅ - csc² ∅ = -1