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MatroZZZ [7]
3 years ago
7

Which is traveling faster, a car whose velocity vector is 201 + 25), or a car whose velocity vector is 30i, assuming that the un

its are the same for both directions? is the faster car. At what speed is the faster car traveling? speed = Enter the speed as a NUMBER, using exact values or at least 4 decimal place accuracy.
Mathematics
1 answer:
ioda3 years ago
7 0

Answer with explanation:

For any object having the velocity vector as

\overrightarrow{v}=v_x\widehat{i}+v_y\widehat{j}+v_z\widehat{k}

the magnitude of velocity is given by

|v|=\sqrt{v_x^2+v_y^2+v_z^2}

For car 1 the velocity vector is

\overrightarrow{v}_1=20\widehat{i}+25\widehat{j}

Therefore

|v_1|=\sqrt{20^2+25^2}\\\\\therefore v_1=32.0156units

Similarly for car 2 we have

\overrightarrow{v}_2=30\widehat{i}

Therefore

|v_2|=\sqrt{30^2}\\\\\therefore v_2=30.0units

Comparing both the values we find that car 1 has the greater speed.

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A textile mill wishes to establish a control procedure on flaws in towels it manufactures. Using an inspection unit of 50 units,
Natasha_Volkova [10]

Answer:

•A c-chart is the appropriate control chart

• c' = 8.5

• Control limits, CL = 8.5

Lower control limits, LCL = 0

Upper control limits, UCL = 17.25

Step-by-step explanation:

A c chart is a quality control chart used for the number of flaws per unit.

Given:

Past inspection data:

Number of units= 100

Total flaws = 850

We now have:

c' = 850/100

= 8.5

Where CL = c' = 8.5

For control limits, we have:

CL = c'

UCL = c' + 3√c'

LCL = c' - 3√c'

The CL stands for the normal control limit, while the UCL and LCL are the upper and lower control limits respectively

Calculating the various control limits we have:

CL = c'

CL = 8.5

UCL = 8.5 + 3√8.5

= 17.25

LCL = 8.5 - 3√8.5

= -0.25

A negative LCL tend to be 0. Therefore,

LCL = 0

4 0
3 years ago
The living room in a new house has the dimensions shown. What is the volume of the room?
irga5000 [103]

Answer:

v = 220 yd²

Step-by-step explanation:

Small portion

v = 5 * 4 * 3

v = 60 yd²

Large portion

v = 9 * 6 * 3

v = 162 yd²

Total

v = 60 + 162

v = 220 yd²

5 0
3 years ago
Please help with this?
Semmy [17]

Answer: Subtract 3 from each side of the equation(A)

Step-by-step explanation:

3n2−15n=3

1:Subtract 3n2 from both sides.

-15n=3-3n2

2:Divide both sides by -15.

-15n/-15=3-3n2/-15

3:Dividing by −15 undoes the multiplication by −15.

n=3-3n2/-15

4:Divide 3−3n 2 ​ by −15

n=n2-1/5

​

​  

 

​  

​  

 

​  

 

4 0
2 years ago
Three teachers lead the math club at school. There are 45 students in the club. What is the ratio of students to teachers?​
AnnZ [28]

Answer:

45 to 3

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Based on Pythagorean identities, which Equation is true?
Pavel [41]
The answer is cot² ∅ - csc² ∅ = -1

Referring to Pythagorean identities: 
sin² ∅ + cos² ∅ = 1
1+cot² ∅ = csc² ∅
tan² ∅ + 1 = sec² ∅

1+cot² ∅ = csc² ∅  
⇒ transposing 1 and csc² ∅ we will have now
cot² ∅ - csc² ∅ = -1
8 0
3 years ago
Read 2 more answers
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