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stellarik [79]
3 years ago
13

PLEASE HELP ME I WILL DO ANYTHING!!

Mathematics
1 answer:
il63 [147K]3 years ago
6 0

Answer:

i’m pretty sure it’s because they make 180°

Step-by-step explanation:

You might be interested in
The admission fee at an amusement park is $2.00 for children and $6.80 for adults. On a certain day, 388 people entered the park
san4es73 [151]

Answer: 188 children and 200 adults were admitted

Step-by-step explanation:

Let x represent the number of children that were admitted.

Let y represent the number of adults that were admitted.

On a certain day, 388 people entered the park. It means that

x + y = 388

The admission fee at the amusement park is $2.00 for children and $6.80 for adults. The admission fees collected on that day totaled $1736. It means that

2x + 6.8y = 1736- - - - - - - - - - 1

Substituting x = 388 - y into equation 1, it becomes

2x + 6.8y = 1736

2(388 - y) + 6.8y = 1736

776 - 2y + 6.8y = 1736

- 2y + 6.8y = 1736 - 776

4.8y = 960

y = 960/4.8

y = 200

x = 388 - y = 388 - 200

x = 188

4 0
3 years ago
Determine the projection of w onto u.
irina [24]

Answer:

A.6.2i-4.2 j

Step-by-step explanation:

We are given that

u=9i-6j

v=-3i-2j

w=19i+15j

We have to find the projection of w on to u.

The project of vector a on b

=\frac{a\cdot b}{\mid b\mid^2}b

w.u=(19i+15j)\cdot (9i-6j)=171-90=81

\mid u\mid=\sqrt{x^2+y^2}=\sqrt{9^2+(-6)^2}=\sqrt{117}

Using the formula

The projection of w on to u

=\frac{u\cdot w}{\mid u\mid^2}(u)=\frac{81}{117}(9i-6j)

The projection of w on to u=6.2i-4.2j

Hence, option A is true.

4 0
3 years ago
Read 2 more answers
Robert earned $10, which was 4 less than twice what Eric earned. How much money<br> did Eric earn?
cestrela7 [59]

Answer:

uh

Step-by-step explanation:

gygygyg

4 0
4 years ago
Please help
Rasek [7]
B is the answer i believe
7 0
3 years ago
Which statement is true about the underlined digit in the number 65,888?
Ghella [55]
Sixty five thousand eight hundred and eighty eight
8 0
4 years ago
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