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oksano4ka [1.4K]
3 years ago
13

A person came to work at 8:30 am, went out at 11:45 am, had lunch, came in at 12:30 pm, and left at 5:15 pm. How many hours did

this person work?
Mathematics
1 answer:
Vlad1618 [11]3 years ago
8 0
Hello!

The person started working at 8:30 and stopped at 11:45 for lunch. That means that person worked 1 hour and 15 minutes before taking a lunch break.

The lunch break doesn't count because the person wasn't "working" then.

Next, this person worked from 12:30 to 5:15, which means they worked 4 hours and 45 minutes.

Add this up with the 1 hour and 15 minutes from before:

4 h 45 min + 1 h 15 min = 6 hours

This person worked a total of 6 hours.
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Esmerelda is five times as old as Ruth. Four years ago, the sum of their ages was 22 years. How old is each now?
Lina20 [59]

Answer:

Ruth is  x+4=7/3+4,   esmerelda  is  5x+4=35/3+4

Step-by-step explanation:

if Ruth is x, esmerelda is 5x,

four years ago,

Ruth is x+4,  esmerelda is 5x+4,  depend on the sum, we get:

x+4+5x+4=22, x=7/3

so:

Ruth is  x+4=7/3+4,   esmerelda  is  5x+4=35/3+4

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lapo4ka [179]

Answer:

D) y\:, y\:>\:-x

Step-by-step explanation:

The blue boundary line has a y-intercept of 2 and a slope of  2.

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y\:

The blue boundary line passes through the origin and has slope -1.

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Since the boundary line is not solid and the right half-plane is shaded, its inequality is y\:>\:-x

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Answer:

x=3

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5 0
3 years ago
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