Answer:
Check for (3, 0)
Put x = 3 and y = 0 in equation 2x – y = 6
2(3) – (0) = 6
6 = 6
<h2>True statement. </h2>
(3,0) is a solution of 2x – y = 6.
(ii) Check for (0, 6)
Put x = 0 and y = 6 in 2x – y = 6
2 x 0 – 6 = 6-6 = 6
<h2>False statement. </h2>
⇒ (0, 6) is not a solution of 2x – y = 6.
(iii) Check for (2, -2)
Put x = 0 and y = 6 in 2x – y = 6
2 x 2 – (-2) = 6
4 + 2 = 6
6 = 6
<h2>True statement. </h2>
⇒ (2,-2) is a solution of 2x – y = 6.
(iv) Check for (√3, 0)
Put x = √3 and y = 0 in 2x – y = 6
2 x √3 – 0 = 6
2√3 = 6
<h2>False statement. </h2>
⇒(√3, 0) is not a solution of 2x – y = 6.
(v) Check for (1/2, -5)
Put x = 1/2 and y = -5 in 2x – y = 6
2 x (1/2) – (-5) = 6
1 + 5 = 6
6 = 6
<h2>True statement. </h2>
⇒ (1/2, -5) is a solution of 2x – y = 6.
Step-by-step explanation:
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