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elena-s [515]
3 years ago
6

Fill in the code in the underlined location to display the mouse point location when the mouse is pressed in the pane.

Computers and Technology
1 answer:
olga nikolaevna [1]3 years ago
6 0

Answer:

Point e = MouseInfo.getPointerInfo().getLocation();

Explanation:

Through the above we can find the point where the mouse is located. And you can check the further code, the details are given how this point is being used to find the x and y value of the location. You are also going to find that we can do almost anything at this location. Remember this code is in JAVA,

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Write code to take a String input from the user, then print the first and last letters of the string on one line. Sample run: En
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<h2>Answer:</h2>

//import the Scanner class to allow for user input

import java.util.Scanner;

//Begin class definition

public class FirstAndLast{

   //Begin the main method

    public static void main(String []args){

       

       

       //****create an object of the Scanner class.

       //Call the object 'input' to receive user's input

       //from the console.

       Scanner input = new Scanner(System.in);

       

       //****create a prompt to tell the user what to do.

       System.out.println("Enter the string");

       

       //****receive the user's input

       //And store it in a String variable called 'str'

       String str =  input.next();

       

       //****get and print the first character.

       //substring(0, 1) - means get all the characters starting

       //from the lower bound (index 0) up to, but not including the upper

       //bound(index 1).

       //That technically means the first character.

       System.out.print(str.substring(0,1));

       

       //****get and print the last character

       //1. str.length() will return the number of character in the string 'str'.

       //This is also the length of the string

       //2. substring(str.length() - 1) - means get all the characters starting

       // from index that is one less than the length of the string to the last

       // index (since an upper bound is not specified).

       // This technically means the last character.

       System.out.print(str.substring(str.length()-1));

       

       

       

    }  // end of main method

   

} //end of class definition

<h2>Explanation:</h2>

The code has been written in Java and it contains comments explaining important parts of the code. Kindly go through the comments.

The source code and a sample output have also been attached to this response.

To run this program, copy the code in the source code inside a Java IDE or editor and save it as FirstAndLast.java

Download java
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> java </span>
4c53f66d970acf88b251b2cf41bcdaf6.png
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. Generate 106 message bits (random binary values (bool/int) ). 2. Generate the corresponding code bits for r = 3, 5. This means
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Answer:

While loops are typically used when you don’t know how many times the loop needs to repeat. The body of the loop will repeat while the condition is true. The logical expression will be evaluated just before the body of the loop is repeated.

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Start by guessing 2.

Compute the guess squared.

Is the guess squared close to the target number? If it’s within 0.01, we’re done. We’ll take the absolute value of the difference, in case we overshoot. (In Python, abs is the absolute value function.)

If it’s not close enough, we divide the target number by our guess, then average that value with our guess.

That’s our new guess. Square it, and go back to Step #3.

Explanation:

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