2 years ago

Years of experience for each

Mathematics

2 answers:

garik1379 [7]2 years ago

6 0

Around 45% since there is 5 with more than 11 years of experience and there is 11 total teachers 5/11 is around 45%

Stella [2.4K]2 years ago

4 0

Answer:

The correct answer is 25%.

Step-by-step explanation:

You might be interested in

Given that p= x-y Find p when : X=-12. And y=-19 What is p?

Mazyrski [523]

Answer:

p=7

Step-by-step explanation:

p=-12-(-19)

p=-12+19

p=7

7 0

2 years ago

Read 2 more answers

Solve for n nn. 7 n − 4 = 31

makkiz [27]

Answer: 5

Step-by-step explanation:

5x7=35

35-4=31

5 0

2 years ago

Read 2 more answers

What is scatter plots

Mumz [18]

Answer: When the data given is spread across the graph at random in no certain order

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

How do you write 0.9 as a percentage?

mamaluj [8]

0.9 as a percentage would be 0.9% it doesn't really change

7 0

2 years ago

What is interest earned on 3500 invested at 6% compounded quarterly or 12 years

enyata [817]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$3500\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &12
\end{cases}
\\\\\\
A=3500\left(1+\frac{0.06}{4}\right)^{4\cdot 12}\implies A=3500(1.015)^{48}$

so, the interest earned then will be A - 3500.

6 0

2 years ago