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VMariaS [17]
3 years ago
5

What is true about the lines Y=7x-10 and Y=7x +10

Mathematics
2 answers:
erik [133]3 years ago
5 0
They would be parallel lines
Juliette [100K]3 years ago
4 0
The answer is that they can be parralel
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B R O<br> H E L P<br> M E<br> T H A N K <br> Y O U : &lt; )
Ksivusya [100]
Rules: (-) plus (-) equals positive.
Anything negative in absolute value will turn positive. Example, | -2 | —> 2

|-4b-8|+|-1 -b^2| +2b^3; b=-2

First step is substituting all the “b” to -2.
|-4(-2) -8| + |-1 -(-2)^2| +2(-2)^3
Then start solving.
|8-8| + |-1 -(4)| +2(-8)
|0| + |-5| -16
0 +5 -16= -11
Answer: -11
4 0
3 years ago
Scientists plan to release a space probe that will enter the atmosphere of a gaseous planet. The temperature of the gaseous plan
vladimir1956 [14]

Answer:

its 450 k

Step-by-step explanation:

It is given that the temperature of the gaseous planet is linearly related with height of the atmosphere. we can write this in the mathematical equation:

y = m x +c

where y is the temperature values, x is height, m is the slope and c is the y-intercept. we have been given two sets of value in the image, using which we can find the value of slope in y-intercept.

at x = 18.40 km, y = 147.54 K

⇒147.54 = 18.40 m + c      

⇒c = 147.54 - 18.40 m  ..(1)

at x =78.11 km, y = 567.00 K

⇒567.00 =78.11 m + c       ..(2)

Put equation 1 in 2 and solve:

⇒567.00 =78.11 m + 147.54 - 18.40 m

⇒419.46 = 59.71 m

⇒ m =419.46 ÷59.71 = 7.025 K/km

c = 147.54 - 18.40 × 7.025 = 18.28 K

At height, x = 61.5 km the approximate temperature is :

y = 7.025 K/km ×  61.5 km + 18.28 K = 450.3 K

Thus, the approximate temperature at altitude 61.5 km is 450 K.

7 0
3 years ago
What is the relationship between ​2.57×104​ and ​2.57×10−1​ ?
Shalnov [3]

Answer:

2.57×104= 267.28

2.57×10-1= 24.7

7 0
2 years ago
Read 2 more answers
I was told that the answer to this is -7 but I don't understand how to get there.
Amiraneli [1.4K]

Answer:

The answer to your question is: - 7

Step-by-step explanation:

                                            3125 = (- 1  - 18t) ⁵/³

                                            (3125)³ = ( -1 - 18t)⁵

                                            (3125)³/⁵ = - 1 - 18t

                                            125 = - 1 - 18t

                                            125 + 1 = - 18t

                                            126 = - 18t

                                            t = 126 / -18

                                            t = -7

3125³ = 3.0518 x 10¹⁰

\sqrt[5]{3.0518 x 10¹⁰} = 125

                       

6 0
3 years ago
Which expdession is equivalent to 4-2(3x-5)​
GalinKa [24]

Answer:

4

Step-by-step explanation:

Your answer would be 0 because you have to subtract 3 by 5 you get the answer 2. Then you subtract 4 by 2 and you 2. After that you multiply 2 by 2 getting the answer 4.

7 0
3 years ago
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