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3 years ago

How are transformations affected by specific values of a constant

1 answer:

OverLord2011 [107]3 years ago

8 0

Adding a constant term to the value of a function could either result to an upward or downward shifts. On the other hand, it may also shift to left or to the right. Functions play a role on transformation as it will display how the graph is moved around.

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Write 350 as a product of primes. Use index notation when giving your answer

Mkey [24]

Answer:

5² x 7 x 2

Step-by-step explanation:

350

= 35 x 10

= 7 x 5 x 5 x 2

= 5² x 7 x 2

8 0

3 years ago

Pls help meh

san4es73 [151]

Answer:

7.1 (7.06 rounded to the tenth)

Step-by-step explanation:

The formula for Area of a Circle is: π·r²

R = Radius

π = pi, or 3.14

As long as you know the formula, this is easy!

In class, you may have already been told that the radius is <em>half </em>of the diameter.

1. Half of 3 ft is 1.5 ft.

2. Plug 1.5 in for r, in your calculator

3. Do the calculation, and you should come out to get 7.06858347058

4. Round it!

Finding area for a circle is satisfying, isn't it? xD

5 0

3 years ago

Which expression is equivalent to square root 55x^7y6/11x^11y^8

Novay_Z [31]

Answer:

$\large\boxed{\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\dfrac{\sqrt5}{x^2y}}$

Step-by-step explanation:

$\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\sqrt{\dfrac{55}{11}\cdot\dfrac{x^7}{x^{11}}\cdot\dfrac{y^6}{y^8}}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=\sqrt{5x^{7-11}y^{6-8}}=\sqrt{5x^{-4}y^{-2}}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt5\cdot\sqrt{x^{-4}}\cdot\sqrt{y^{-2}}=\sqrt5\cdot\sqrt{x^{(-2)(2)}}\cdot\sqrt{y^{(-1)(2)}}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt5\cdot\sqrt{(x^{-2})^2}\cdot\sqrt{(y^{-1})^2}\qquad\text{use}\ \sqrt{a^2}=a$

$=\sqrt5\cdot x^{-2}\cdot y^{-1}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\to a^{-1}=\dfrac{1}{a}\\\\=\sqrt5\cdot\dfrac{1}{x^2}\cdot\dfrac{1}{y}=\dfrac{\sqrt5}{x^2y}$

6 0

3 years ago

One number is 7 times another number. The product of the two numbers is 252. Find the two numbers.

Nitella [24]

Step-by-step explanation:

x =7y ----(1)

xy=252 ----(2)

(1) into (2):

(7y)(y) = 252

$7 {y}^{2} = 252 \\ 7y = \sqrt{252}$

7y=15.874....

y=2.27

y value into (1)

x= 7(2.268)

x=15.87

the two numbers are 15.87 and 2.27 (Ans)

6 0

3 years ago

Will mark BRAINLIST Find the perimeter of the following shape, rounded to the nearest tenth: coordinate plane with quadrilateral

kolbaska11 [484]

Answer:

11.3 units

Step-by-step explanation:

Let's find the length of one of the boxes.

$a^2+b^2=c^2\\1^2+1^2=c^2\\1+1=c^2\\2 = c^2\\\\\sqrt{2} = c\\ c = 1.414...$

Let's simplify c down to 1.41.

Now, there are 8 of these little boxes for the perimeter, let's multiply.

$1.41\cdot8=11.28$

That can be simplified to the nearest tenth - 11.3

Hope this helped!

8 0

3 years ago