Question

Write the equation of the line that passes through (−3, 5) and (2, 10) in slope-intercept form

Answer 1

Slope = (10 -5)/(2+3) = 5/5=1

y = mx + b
5 = 1(-3) + b
b =8

so equation y = x +8

answer: y = x + 8(first choice)

Answer 2

Answer:

The slope-intercept form is $y=x+8$

Step-by-step explanation:

Given points are (-3, 5) and (2,10). Now, we have to find the equation of the line that passes through these points in slope-intercept form.

Equation of line passing through the point (x', y') can be written as

$y-y'=m(x-x')$  where m is $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Hence, the equation can be written as $(y-5)=\frac{10-5}{2-(-3)}(x-(-3))$

⇒ $y-5=\frac{5}{5}(x+3)$

⇒ $y=x+3+5$

⇒$y=x+8$

which is slope-intercept form where slope is 1 and intercept is 8 by comparing with y=mx+c