A., B., C., D., are NOT true. I think this is a trick question. Lol
3bc is the answer to your problem
Answer:
Hi!
Explanation:
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<h3>
Answer:</h3>
- A) p = 5, one solution
- B) no solutions
- C) infinite solutions
<h3>
Step-by-step explanation:</h3>
A) Add 19-5p to each side of the equation:
... 10 = 2p
... 5 = p . . . . . divide by the coefficient of p
B) Subtract 5p from both sides of the equation:
... -9 = -19 . . . . . there is <em>no value of p</em> that will make this true. (No solution.)
C) Subtract 5p from both sides of the equation:
... -9 = -9 . . . . . this is true for <em>every value of p</em>. (Infinite solutions.)
Answer:
Step-by-step explanation:
Since they already have a common denominator of x+1 we can add the numerators
(2x+4-x+5)/(x+1)
(x+9)/(x+1)