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Genrish500 [490]
3 years ago
12

Is (2,-5) is an answer to 4+3x=-2y

Mathematics
1 answer:
bearhunter [10]3 years ago
4 0
Yes. For example x=-1 and y=-1/2
You might be interested in
Please help and explain ( Brainliest for answer!)
Novosadov [1.4K]

Answer:

AD = 3

Step-by-step explanation:

Pythagoras theorem formula: a² + b² = c² (c being the hypotenuse, the longest side of the triangle).

Using this formula, you can easily say that c²-b²=a². c=5, b=4, making the equation 5² - 4² = a ².

Expanding the formula, you'll get 25 - 16 = a².

25 - 16 = 9.

This means that 9 = a².

To find a, you need to root 9. Using a calculator, you'll know that this number is 3, meaning that AD = 3.

7 0
3 years ago
What is the answer? <br>x+y=15 <br>-2x+5y=-2​
zavuch27 [327]
Multiply the first equation by 2

2x + 2y =30

now we’ll add the second equation to the first equation

2x + 2y =30
-2x+5y= -2

7y=28

divide by 7

y=4

now plug y back into the first equation

x + 4 = 15

subtract 4

x=11
6 0
3 years ago
Is it possible to have a triangle with 150 20 20 degrees angle and why ?
OLga [1]

No, it is not possible.  The total measure of all angles in a triangle must be 180.  If you add these three together, you get 190.

4 0
3 years ago
I HAVE AN EXAM PLEASE HELP ME GET THE ANSWER
sesenic [268]
Answer: The ladder is 5.3 m long
Step by step solution
1. Draw out the scenario, ie a right triangle where the hypotenuse is the ladder, the wall is 4.5m and the angle the ladder and the ground makes 58 degree.

2. Soh, Cah, Toa
The wall is opposite, the ground is adjacent, and the ladder is hypotenuse
Sine (58) = 4.5/h

3. Solve for hypotenuse
h * sine (58) = 4.5
h = 4.5/sine (58)
h = ~ 5.3 m
3 0
3 years ago
How many times will the digit "3" appear if we write all whole numbers from 1-9999?
Marysya12 [62]

Answer:

4000

Step-by-step explanation:

from 1 - 1000 = 300

1's    = 100

10's  = 100

100's = 100

1000's = 0

300 * 10 = 3000

then add in all the 3000's (ie 3001,3002, etc ) that adds one more thousand

3000 + 1000 = 4000

5 0
3 years ago
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