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denpristay [2]
3 years ago
5

What is a mathematical expression indicating to a root of a quantity?

Mathematics
1 answer:
vladimir1956 [14]3 years ago
7 0
Find out smarty don’t cheat
You might be interested in
Find the measure of angle A
blagie [28]

Answer:

43°

Step-by-step explanation:

(x + 53)° + (x + 74)° + 73° = 180°

(x + 53 + x + 74)° = 180° - 73°

(2x + 127)° = 107°

2x + 127 = 107

2x = 107 - 127

2x = - 20

x = - 20/2

x = - 10

m\angle A = (x +53)\degree \\\\m\angle A = (-10 +53)\degree \\\\m\angle A = 43\degree \\\\

4 0
3 years ago
Two runners are saving money to attend a marathon. The first runner has $112 in savings, received a $45 gift from a friend, and
Tcecarenko [31]
Hope this helps but I think the answer could be : 157+25m=50+60m
4 0
4 years ago
Read 2 more answers
4.
tiny-mole [99]

Answer:

7

Step-by-step explanation:

7 =2 hx x e

8 0
3 years ago
Which equation applies the associative property of multiplication?
ohaa [14]

Answer:

<u>C) −12/5⋅(7/12⋅1/9)⋅8/5=(−12/5⋅7/12)⋅(1/9⋅8/5)</u>

5 0
3 years ago
A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex
Olenka [21]

Answer:

a

 The  90% confidence interval that  estimate the true proportion of students who receive financial aid is

     0.533  <  p <  0.64

b

   n = 1789

Step-by-step explanation:

Considering question a

From the question we are told that

      The sample size is  n = 200

      The number of student that receives financial aid is k = 118

Generally the sample proportion is  

      \^ p = \frac{k}{n}

=>   \^ p = \frac{118}{200}

=>   \^ p = 0.59

From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90 ) \%

=>   \alpha = 0.10

Generally from the normal distribution table the critical value  of \frac{\alpha }{2}  is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

 =>E =  1.645 * \sqrt{\frac{0.59 (1- 0.59)}{200} }

=>  E = 0.057

Generally 90% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

  =>  0.533  <  p <  0.64  

Considering question b

From the question we are told that

    The margin of error  is  E = 0.03

From the question we are told the confidence level is  99% , hence the level of significance is    

      \alpha = (100 - 99 ) \%

=>   \alpha = 0.01

Generally from the normal distribution table the critical value  of   is  

   Z_{\frac{\alpha }{2} } = 2.58

Generally the sample size is mathematically represented as      

        [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=>      n = [\frac{2.58}{0.03} ]^2 * 0.59 (1 - 0.59 )

=>      n = 1789

8 0
3 years ago
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