Answer:
D No. as there are only 12 bolts longer than 1inch.
Mr. Slivka needs 16 bolts of greater than 1 measure, and there are only 12.
Step-by-step explanation:
We cannot include 1 inch data as this is not over 1 inch like the 1inch 2/8 and 1inch 4/8 etc. the greater measures of over 1 inch count to 12.
We know they are greater as they do not have a negative sign next to the added fraction of 1 2/8 or 1 4/8.
1/2 + 3/x = 3/4
multiply everything by x
1/2x + 3 = 3/4x...subtract 1/2x from both sides
3 = 3/4x - 1/2x
3 = 3/4x - 2/4x
3 = 1/4x...multiply both sides by 4
4 * 3 = x
12 = x
Answer:
the answer is D
Step-by-step explanation:
TOOK THE TEST
5.8/ sqrt 80=0.648 I think you are asking for the standard margin
Hope this works
For question number 1:The plot H = H(t) is the parabola and it reaches its maximum in the moment when exactly at midpoint between the roots t = 0 and t = 23. At that moment t = 23/2 or 11.5 seconds.
For question number 2:To find the maximal height, just simply substitute t = 11.5 into the quadratic equation. The answer would be 22.9.
For question number 3:H(t) = 0, or, which is the same as -16t^2 + 368t = 0.Factor the left side to get -16*t*(t - 23) = 0.t = 0, relates to the very start of the process, when the ash started its way up.The other root is t = 23 seconds, and it is precisely the time moment when the bit of ash will go back to the ground.
