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lubasha [3.4K]
3 years ago
8

Three times a number, added to 9 is 33 find the number

Mathematics
2 answers:
kozerog [31]3 years ago
6 0
3 x 8 = 24 
24 + 9 = 33

"the number" = 8
Rainbow [258]3 years ago
6 0
3x+9=33

3(8)+9=33

24+9=33
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Solve the following inequality. 45 < 9(x + 3) < 153 A. 8 < x < 14 B. 2 < x < 20 C. 8 < x < 20 D. 2 <
kaheart [24]

Answer:

B

Step-by-step explanation:

hope this help but I worked it out so it should be true

7 0
3 years ago
The input value 2.
Irina18 [472]
Your answer is 9.

Since you have

2(2)^2 you get 2(4) which is 8.

Then you have -3(2) which is -6.

Lastly you have the 7.

When you add it up you get.

9
5 0
3 years ago
Explain how to divide 3/4 ÷ 3/8 by using reciprocal of 3/8​
sertanlavr [38]

The reciprocal of 3/8 would be 8/3 (basically reversing the numbers).

When dividing fractions, you can just multiply the first fraction by the reciprocal of the second fraction instead of dividing by the second fraction.

3/4 ÷ 3/8

= 3/4 × 8/3

Simplifying gives us the final answer:

= 2

Let me know if you need any clarifications, thanks!

5 0
3 years ago
What divided by 6 equals 7
vivado [14]

Answer:

42

Step-by-step explanation:

You can prove this by taking 42 and dividing it by 6, and you will see that the answer is 7. Tip: For future reference, when you are presented with a problem like "What divided by 6 equals 7?", all you have to do is multiply the two known numbers together.

6 0
3 years ago
Read 2 more answers
In this problem we consider an equation in differential form Mdx+Ndy=0. (4x+2y)dx+(2x+8y)dy=0 Find My= 2 Nx= 2 If the problem is
zheka24 [161]

Answer:

f(x,y)=2x^2+4y^2+2xy=C_1\\\\Where\\\\y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )

Step-by-step explanation:

Let:

M(x,y)=4x+2y\\\\and\\\\N(x,y)=2x+8y

This is and exact equation, because:

\frac{\partial M(x,y)}{\partial y} =2=\frac{\partial N}{\partial x}

So, define f(x,y) such that:

\frac{\partial f(x,y)}{\partial x} =M(x,y)\\\\and\\\\\frac{\partial f(x,y)}{\partial y} =N(x,y)

The solution will be given by:

f(x,y)=C_1

Where C1 is an arbitrary constant

Integrate \frac{\partial f(x,y)}{\partial x} with respect to x in order to find f(x,y):

f(x,y)=\int\ {4x+2y} \, dx =2x^2+2xy+g(y)

Where g(y) is an arbitrary function of y.

Differentiate f(x,y) with respect to y in order to find g(y):

\frac{\partial f(x,y)}{\partial y} =2x+\frac{d g(y)}{dy}

Substitute into \frac{\partial f(x,y)}{\partial y} =N(x,y)

2x+\frac{dg(y)}{dy} =2x+8y\\\\Solve\hspace{3}for\hspace{3}\frac{dg(y)}{dy}\\\\\frac{dg(y)}{dy}=8y

Integrate \frac{dg(y)}{dy} with respect to y:

g(y)=\int\ {8y} \, dy =4y^2

Substitute g(y) into f(x,y):

f(x,y)=2x^2+4y^2+2xy

The solution is f(x,y)=C1

f(x,y)=2x^2+4y^2+2xy=C_1

Solving y using quadratic formula:

y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )

4 0
3 years ago
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