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ycow [4]
3 years ago
14

{ y = 4x

Mathematics
1 answer:
Aliun [14]3 years ago
4 0
Y= 4×
4×+y=0
You substitute
Y= 4×(4)+y= 0
Y= 16×+y=0
Subtract y
Y=16×+y=0
-y -y
16×=0
Divide 16 by 0
X=0
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Subtract -2k3 + k2 - 9 from 5k3 - 3k + 7.
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basically rewrite with simple algebra principles
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I need help with this math question
ICE Princess25 [194]

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B. 5

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Step 1: Rewrite the equation a bit

\frac{7^\frac{3}{4}}{7^\frac{x}{8}}=\sqrt[8]{7}\\7^\frac{3}{4}^-^\frac{x}{8}=7^\frac{1}{8}

Step 2: Place a logarithm base 7 on both sides

7^\frac{3}{4}^-^\frac{x}{8}=7^\frac{1}{8}\\log_77^\frac{3}{4}^-^\frac{x}{8}=log_77^\frac{1}{8}\\(\frac{3}{4}-\frac{x}{8})log_77=\frac{1}{8}log_77\\(\frac{3}{4}-\frac{x}{8})1=\frac{1}{8}1\\\frac{3}{4}-\frac{x}{8}=\frac{1}{8}

Step 3: Solve for x

\frac{3}{4}-\frac{x}{8}=\frac{1}{8}\\\frac{6}{8}-\frac{x}{8}=\frac{1}{8}\\-\frac{x}{8}=-\frac{5}{8}\\\frac{x}{8}=\frac{5}{8}\\x=5

Neat exponent question :)

7 0
3 years ago
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