Hello please help me I don't get this at all

Mathematics

2 answers:

bezimeni [28]2 years ago

7 0

The area is 49 because the formula for finding the area of trapezoid is A=
((a+b)/2)h. Basically, you add the top and bottom bases and divide it by 2 then multiply it by the height.

Stella [2.4K]2 years ago

4 0

There are 1 rectangle and 2 triangles.
The area of the rectangle is 5 x 7 =35
The are of the triangle is 7 x 2 = 14(1/2) = 7
There are 2 triangles, so 7 x 2 = 14

14 + 35 = 49

49 is your answer

hope this helps

You might be interested in

Comparing to Internet service plans plan one cost $34.99 per month plan to cost $134.97 every three months if Crystal plans to s

Ket [755]

Plan 1 because she spends 435.88 more if she goes with plan 2

5 0

2 years ago

Round 877.71 to the nearest tenth

Rainbow [258]

The 7 after the decimal is in the tenths place, so look at the one in the hundredths place. It is less than 5, so the 7 is not rounded up and stays 7. 877.7 is 877.71 rounded to the nearest tenth.

4 0

3 years ago

Read 2 more answers

Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your

Darina [25.2K]

Answer:

Given definite integral as a limit of Riemann sums is:

$\lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]$

Step-by-step explanation:

Given definite integral is:

$\int\limits^7_4 {\frac{x}{2}+x^{3}} \, dx \\f(x)=\frac{x}{2}+x^{3}---(1)\\\Delta x=\frac{b-a}{n}\\\\\Delta x=\frac{7-4}{n}=\frac{3}{n}\\\\x_{i}=a+\Delta xi\\a= Lower Limit=4\\\implies x_{i}=4+\frac{3}{n}i---(2)\\\\then\\f(x_{i})=\frac{x_{i}}{2}+x_{i}^{3}$

Substituting (2) in above

$f(x_{i})=\frac{1}{2}(4+\frac{3}{n}i)+(4+\frac{3}{n}i)^{3}\\\\f(x_{i})=(2+\frac{3}{2n}i)+(64+\frac{27}{n^{3}}i^{3}+3(16)\frac{3}{n}i+3(4)\frac{9}{n^{2}}i^{2})\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{3}{2n}i+\frac{144}{n}i+66\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{291}{2n}i+66\\\\f(x_{i})=3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]$