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Luden [163]
3 years ago
5

Given A = {(1, 3)(-1, 5}(6, 4)}, B = {(2, 0)(4, 6)(-4, 5)(0, 0)} and C = {(1, 1)(0, 2)(0, 3)(0, 4)(-3, 5)}, answer the following

multiple choice question:
From the list of sets A, B, and C above, choose the set of relations that correctly represents a function.
Set A only
Sets A and C only
Sets A and B only
Mathematics
2 answers:
masya89 [10]3 years ago
4 0
Sets A and B only. Set C has the x value repeating so it is not a function. 
laila [671]3 years ago
3 0

Answer:

Set A and B only

Step-by-step explanation:

We are given that

A={(1,3),(-1,5),(6,4)}

B={(2,0),(4,6),(-4,5),(0,0)}

C={(1,1),(0,2),(0,3),(0,4),(-3,5)}

We are given that sets A, B and C represent the relations .

We have to choose the set of  relations that correctly represents a function

Function: It a mapping between two sets A and B. Every element of set A has unique image in set B.More than one image of an element cannot be possible or an element cannot have more than one image.Two elements or more than  two elements have same image.

In set A, each element is related with unique element.

Image of 1=3

Image of -1=5

Image of 6=4

Therefore, A represents a function.

In set B, Every element is related to a unique element.

Image of 2=0

Image of 4=6

Image of -4=5

Image of 0=0

Hence, B represents a function .

In set C

Image of 1=1

Image of 0=2

Image of 0=3

Image of 0=4

Image of -3=5

By definition of function, each element have only one image.

But 0 have more than one image.

Therefore, C does not represents  function.

Set A and B only represents a function

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Roman55 [17]

Answer:

(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}

(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}

Step-by-step explanation:

Given system of equations:

\begin{cases}y=x^2-9\\y=4x-4\end{cases}

To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:

\begin{aligned}x^2-9&=4x-4\\x^2-4x-9&=-4\\x^2-4x-5&=0\end{aligned}

Factor the quadratic:

\begin{aligned}x^2-4x-5&=0\\x^2-5x+x-5&=0\\x(x-5)+1(x-5)&=0\\(x+1)(x-5)&=0\end{aligned}

Apply the <u>zero-product property</u> and solve for x:

\implies x+1=0 \implies x=-1

\implies x-5=0 \implies x=5

Substitute the found values of x into the <u>second equation</u> and solve for y:

\begin{aligned}x=-1 \implies y&=4(-1)-4\\y&=-4-4\\y&=-8\end{aligned}

\begin{aligned}x=5 \implies y&=4(5)-4\\y&=20-4\\y&=16\end{aligned}

Therefore, the solutions are:

(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}

(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}

6 0
1 year ago
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yuradex [85]

Answer:

Step-by-step explanation:

One of the cars are blue. it can travel 31 1/2 miles on 1 1/4 gallons of gasoline. Converting 31 1/2 miles to decimal, it becomes 31.5 miles. Converting 1 1/4 gallons of gasoline to decimal, it becomes 1.25 gallons of gasoline.

Therefore, the miles per gallon for the blue car is

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Converting 28 4/5 miles to decimal, it becomes 28.8 miles. Converting 4/5 gallons of gasoline to decimal, it becomes 0.8 gallons of gasoline.

Therefore, the miles per gallon for the red car is

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6 0
2 years ago
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sattari [20]

Answer:

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To do this plug in 3.4 for each version of p. The only one that would be true would be J.

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What is the answer to this question?
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