(x - 4)² + (y - 11)² = 100 . The center of the circle is at the point ( 4, 11) and radius is 10
Answer:
u gonna get a warning dude
Step-by-step explanation:
Answer:
The triangle ABC is an isosceles right triangle
Step-by-step explanation:
we have
The coordinates of triangle ABC are
A (0, 2), B (2, 5), and C (−1, 7)
we know that
An isosceles triangle has two equal sides and two equal internal angles
The formula to calculate the distance between two points is equal to
step 1
Find the distance AB
substitute in the formula
step 2
Find the distance BC
substitute in the formula
step 3
Find the distance AC
substitute in the formula
step 4
Compare the length sides
therefore
Is an isosceles triangle
Applying the Pythagoras Theorem
substitute
-----> is true
therefore
Is an isosceles right triangle
Answer:
BC ≈ 14.5 cm
Step-by-step explanation:
Using the sine ratio in the right triangle
sin65° = = = ( multiply both sides by 16 )
16 × sin65° = BC , then
BC ≈ 14.5 cm ( to the nearest tenth )
The correct answer is: [B]: "40 yd² " .
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First, find the area of the triangle:
The formula of the area of a triangle, "A":
A = (1/2) * b * h ;
in which: " A = area (in units 'squared') ; in our case, " yd² " ;
" b = base length" = 6 yd.
" h = perpendicular height" = "(4 yd + 4 yd)" = 8 yd.
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→ A = (1/2) * b * h = (1/2) * (6 yd) * (8 yd) = (1/2) * (6) * (8) * (yd²) ;
= " 24 yd² " .
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Now, find the area, "A", of the square:
The formula for the area, "A" of a square:
A = s² ;
in which: "A = area (in "units squared") ; in our case, " yd² " ;
"s = side length (since a 'square' has all FOUR (4) equal side lengths);
A = s² = (4 yd)² = 4² * yd² = "16 yd² "
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Now, we add the areas of BOTH the triangle AND the square:
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→ " 24 yd² + 16 yd² " ;
to get: " 40 yd² " ; which is: Answer choice: [B]: " 40 yd² " .
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