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MrRa [10]
3 years ago
12

Select the GCF of these numbers. 48 and 60

Mathematics
1 answer:
Andru [333]3 years ago
6 0
The answer is a, 2^2 * 3

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John wants to create a line of dominoes 18 inches long with each domino spaced 1 1/2 in.apart.how many dominoes will he need
AysviL [449]

Answer:

12

Step-by-step explanation:

if the line is 18 inches long and a 1.5 space apart then u divide them and 18 divided by 1.5 is 12

7 0
3 years ago
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Three times a number, subtracted from 20, is equal to -7
tia_tia [17]
The answer is 20-3x=-7 explanation
4 0
2 years ago
P L E A S E H E L P!!!!!!!!!
Nostrana [21]

Answer:

The equation that matches the function shown is option;

C. y = sin\left (\dfrac{1}{2} \cdot x\right)

Step-by-step explanation:

The given graph of the function is a sinusoidal graph

The values of 'x' and 'y' coordinates at the maximum, x-intercept and minimum points are given as follows;

x, {}      y

0    {}   0

π {}       1

2·π   {} 0

3·π {}    -1

4·π {}    0

We note that sin(π/2) = 1, sin(π) = 0 sin(3·π/2) = -1, and sin(4·π/2) = sin(2·π) = 0

Therefore;

y = the sine of half the x-value

Which is presented as follows;

y = sin\left (\dfrac{1}{2} \cdot x\right).

5 0
2 years ago
Convert 1 cal/(m^2 * sec * °C) into BTU/(ft^2 * hr * °F)
Crazy boy [7]

Answer:

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

Step-by-step explanation:

To find : Convert 1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C} into \frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

Solution :

We convert units one by one,

1\text{ m}^2=10.7639\text{ ft}^2

1\text{ sec}=\frac{1}{3600}\text{ hour}

1\text{ cal}=0.003968\text{ BTU}

Converting temperature unit,

^\circ C\times \frac{9}{5}+32=^\circ F

1^\circ C\times \frac{9}{5}+32=33.8^\circ F

So, 1^\circ C=33.8^\circ F

Substitute all the values in the unit conversion,

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{10.7639\times \frac{1}{3600}\times 33.8}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{0.101061}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

Therefore, The conversion of unit is 1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

3 0
3 years ago
What is the value of 5a + 7b <br> if a = 4 and b = 3?? <br> a : 41<br> b : 12<br> c : 43 <br> d : 35
MAXImum [283]
<h3>Answer:</h3><h3>41</h3><h3>Step-by-step explanation:</h3><h3>multiplication and addition</h3><h3>5x4=20</h3><h3>7x3=21</h3><h3>20+21=41</h3>
8 0
2 years ago
Read 2 more answers
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