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Sloan [31]
3 years ago
10

The midpoint of AB is M(1, -1). If the coordinates of A are (7,-4), what are the

Mathematics
1 answer:
Lapatulllka [165]3 years ago
6 0

Answer:

work is attached and shown

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A rectangular prism has a length of 20 meters, a height of 12 meters, and a width of 12 meters. What is its volume, in cubic met
ivanzaharov [21]

Answer:

2880

Step-by-step explanation:

V=whl=12·12·20=2880

3 0
2 years ago
Help! Algebra!!!
balandron [24]
Thet contradict each other, that's why both of them are incorrect.
<span>Suppose that a polynomial has four roots: s, t, u, and v. If the polynomial were evaluated at any of these values, it would have to be zero. Therefore, the polynomial can be written in this form. 

p(x)(x - s)(x - t)(x - u)(x - v), where p(x) is some non-zero polynomial 

This polynomial has a degree of at least 4. It therefore cannot be cubic. 

Now prove Kelsey correct. We have already proved that there can be no more than three roots. To prove that a cubic polynomial with three roots is possible, all we have to do is offer a single example of that. This one will do. 

(x - 1)(x - 2)(x - 3) 

This is a cubic polynomial with three roots, and four or more roots are not possible for a cubic polynomial. Kelsey is correct. 

Incidentally, if this is a roller coaster we are discussing, then a cubic polynomial is not such a good idea, either for a vertical curve or a horizontal curve. I hope this helps</span><span>
</span>
4 0
3 years ago
Which linear inequality is graphed with y &gt;x-2 to
jek_recluse [69]

Answer:

D

Step-by-step explanation:

It's D on Edge, hope this helps

3 0
2 years ago
7/9 - 2/3 and 2/3 - 1/6 <br>​
arsen [322]

Answer:

The answer is 1/9 and 1/2

7 0
3 years ago
Read 2 more answers
If numerator is 2 less than the denominator of a rational number and when 1 is subtracted from numerator and denominator both, t
xenn [34]

Answer:

\frac{3}{5}

Step-by-step explanation:

  • Let the denominator be x
  • So, numerator = x - 2
  • According to the given condition: when 1 is subtracted from numerator and denominator both, the resulting new rational number in its simplest form is \frac{1}{2}

  • \implies \frac{x-2-1}{x-1}=\frac{1}{2}

  • \implies \frac{x-3}{x-1}=\frac{1}{2}

  • \implies 2(x-3)=x -1

  • \implies 2x-6=x -1

  • \implies 2x-x=6-1

  • \implies x=5

  • \implies x-2=-5-2= 3

  • Required \: rational\: number = \frac{3}{5}
6 0
2 years ago
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