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TEA [102]
3 years ago
8

(4y a - 6x b )(4y a + 6x b )

Mathematics
1 answer:
Lina20 [59]3 years ago
8 0
16a square y square -36 b square x 2
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5 cm
Anettt [7]

Step-by-step explanation:

it's 22 due to the sum all the 2 smallest sides bigger than the biggest

5 0
2 years ago
Given x=-3, y=6, and z=-4 xz/-2y
zimovet [89]

Answer:

-1

Step-by-step explanation:

sub in the values of x, y and z into the equation

you get:

(-3)(-4)/(-2)(6)

= 12/-12

= -1

8 0
3 years ago
Read 2 more answers
In a group of Explore students, 38 enjoy video games, 12 enjoy going to the movies and 24 enjoy solving mathematical problems. O
Elodia [21]

Answer:

The number of students that like only two of the activities are 34

Step-by-step explanation:

Number of students that enjoy video games, A = 38

Number of students that enjoy going to the movies, B = 12

Number of students that enjoy solving mathematical problems, C = 24

A∩B∩C = 8

Here we have;

n(A∪B∪C) = n(A) + n(B) + n(C) - n(A∩B) - n(B∩C) -n(A∩C) + n(A∩B∩C)

= 38 + 12 + 24 - n(A∩B) - n(B∩C) -n(A∩C) + 8

Also the number of student that like only one activity is found from the following equation;

n(A) - n(A∩B) - n(A∩C) + n(A∩B∩C) + n(B) - n(A∩B) - n(B∩C) + n(A∩B∩C) + n(C) - n(C∩B) - n(A∩C) + n(A∩B∩C) = 30

n(A) + n(B) + n(C) - 2·n(A∩B) - 2·n(A∩C) - 2·n(B∩C) + 3·n(A∩B∩C) = 30

38 + 12 + 24 - 2·n(A∩B) - 2·n(A∩C) - 2·n(B∩C) + 24 = 30

- 2·n(A∩B) - 2·n(A∩C) - 2·n(B∩C) = -68

n(A∩B) + n(B∩C) + n(A∩C) = 34

Therefore, the number of students that like only two of the activities = 34.

8 0
3 years ago
The number of students enrolled at a college is 12,000 and grows 3% each year.
RideAnS [48]
159 i don’t know for sure tho
4 0
3 years ago
A line has the equation -5x -14y +168 = 0
valkas [14]

Answer:

y = -5/14x + 12

Step-by-step explanation:

add 14y to both sides to isolate variables and divide everything by 14 to get 1y and boom

6 0
2 years ago
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