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vaieri [72.5K]
3 years ago
11

Suppose a system of two linear equations has one solution. What must be true about the graphs of the two equations?

Mathematics
2 answers:
Neporo4naja [7]3 years ago
3 0

Answer:

They intersect at one point.

Step-by-step explanation:

If a system of two linear equations has one solution then the two lines intersect at one point. The solution is the point of intersection.

adell [148]3 years ago
3 0
They intersect at one point
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gtnhenbr [62]

Answer:

(0,1)(4,9)

Step-by-step explanation:

8 0
3 years ago
Which expression is equivalent to (3^2)^-2?<br> A.)–81<br> B.)–12<br> C.)1/18<br> D.)1/12
kobusy [5.1K]
(3^2)^-2
9
9^-2 = 1/9^2 ---> 1/81
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7 0
4 years ago
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Akimi4 [234]

9514 1404 393

Answer:

  the multiplicity is 4

Step-by-step explanation:

The graph shows a root at x = -2 that has a multiplicity of 2. You know the multiplicity is even, because the graph does not cross the x-axis. The multiplicity is 2 because the general shape of the graph in that area matches that of a quadratic (parabola).

The multiplicity of the root at x=4 is also an even number, because the x-axis is not crossed. However, the graph is significantly flatter at that point (than at x=-2), meaning the multiplicity is greater than 2. It is at least 4.

When we draw a graph with a multiplicity of 6 at x=4, we find the ratio of the peaks near x=-4 and x=0 to be different from that shown here. The suggests that the multiplicity of the root at x=4 is exactly 4.

4 0
3 years ago
Now, evaluate f (x) = 2x4 – 4x3 – 11x2 + 3x – 6 for x = –2.<br><br> f (–2) =
lorasvet [3.4K]

Answer:

f(- 2) =  8

Step-by-step explanation:

To evaluate f(- 2) substitute x = - 2 into f(x) , that is

f(- 2) = 2(-2)^{4} - 4(- 2)³ - 11(- 2)² +3(- 2) - 6

       = 2(16) - 4(- 8) - 11(4) - 6 - 6

      = 32 + 32 - 44 - 12

      = 64 - 56

      = 8

3 0
3 years ago
Read 2 more answers
Please help I really need it
natulia [17]

Answer:

1 Mirror images across the y axis

2 Mirror images across the x axis

Step-by-step explanation:

3 0
3 years ago
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