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4 years ago

8

Tyrone want to the park to go jogging the beginning of the running pack has an elevation of -2 free the highest elevation of the

jogging path is 14 feet what is the difference in elevation between the highest point in the beginning of the pack

1 answer:

Hatshy [7]4 years ago

4 0

The difference of -2 to 14 is 16

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Example of the sistributive property 3x6

Margarita [4]

An example for the distributive property would be 3(1x6)

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3 years ago

How do you do this question?

erik [133]

Step-by-step explanation:

Use the first fundamental theorem of calculus.

∫₆¹⁰ f'(x) dx = f(10) − f(6) = 8 − 8 = 0

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3 years ago

A random sample of 864 births in a state included 426 boys. Construct a 95% confidence interval estimate of the proportion of bo

oksian1 [2.3K]

Using the z-distribution, it is found that the 95% confidence interval is (0.46, 0.526), and it does not provide strong evidence against that belief.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

We have that a random sample of 864 births in a state included 426 boys, hence the parameters are given by:

$n = 864, \pi = \frac{426}{864} = 0.493$

Then, the bounds of the interval are given by:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.493 - 1.96\sqrt{\frac{0.493(0.507)}{864}} = 0.46$

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.493 + 1.96\sqrt{\frac{0.493(0.507)}{864}} = 0.526$

The 95% confidence interval estimate of the proportion of boys in all births is (0.46, 0.526). Since the interval contains 0.506, it does not provide strong evidence against that belief.

More can be learned about the z-distribution at brainly.com/question/25890103

4 0

2 years ago

Translation: 4 units left and 4 units up<br> J(−1, −2), A(−1, 0), N(3, −3)

Molodets [167]

Answer:

(-5,2), (-5,4), and (-1,1)

Step-by-step explanation:

3 0

3 years ago

Mrs. Chen's students are making and decorating gift boxes for a nursing home. If the boxes are 7 inches wide, 7 inches long, and

pishuonlain [190]

Answer:

$84\text{ in}^2$ .

Step-by-step explanation:

We have been given that Mrs. Chen's students are making and decorating gift boxes for a nursing home. The boxes are 7 inches wide, 7 inches long, and 7 inches high. We are asked to find the amount of cardboard that is needed for each box.

We will use surface area of cuboid formula to solve our given problem.

$SA=2(lw+lh+hw)$ , where,

l = Length,

w = Width,

h = Height

$SA=2(7\text{ in}\cdot7\text{ in} +7\text{ in}\cdot7\text{ in}+7\text{ in}\cdot7\text{ in})$

$SA=2(14\text{ in}^2+14\text{ in}^2+14\text{ in}^2)$

$SA=2(42\text{ in}^2)$

$SA=84\text{ in}^2$

Therefore, Mrs Chen needs 84 square inches of cardboard.

3 0

3 years ago