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scZoUnD [109]
3 years ago
9

What is the value 6x^2-13 for x=2

Mathematics
1 answer:
salantis [7]3 years ago
7 0

6x^{2}-13 while x=2. Inorder to solve this, we must substitute x with its value.

6 \times 2^{2}-13

=6 \times 4-13

=24-13

=11

Therefore, the answer is 11.

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Jovita divides $12,000 into three investments: a savings account paying 4% annual interest, a bond paying 6%, and a money market
xenn [34]

Answer:

$2080 was invested in the savings account, $4241 was invested in the bond account, & $6539 was invested in the money fund.

Step-by-step explanation:

Let a, b, and c be the fractions of the $12,000 that is invested in the savings, bond, & money fund respectively.

Let S1, S2, S3 be the total monies from the savings, bond, & money fund after the year with interest respectively.

We know that a+b+c=1

and

S1+S2+S3 = 12000 + 860

S1+S2+S3 = 12860

From, the question, we know that b = 2a, and c = 1 - 3a based on the condition of 2 times more in the bond account that the savings account.

Thus;

S1 = a(12000)(1.04) = 12480a

S2 = 2a(12000)(1.06) = 25,440a

S3 = (1 - 3a)(12000)(1.09) = 13080 - 39240a

We already know that;

S1+S2+S3 = 12860

Thus, Adding the 3 equations gives;

12480a + 25,440a + 13080 - 39240a = 12860

Thus, simplifying gives;

13080 - 12860 = 39240a - 12480a - 25,440a

220 = 1320a

a = 220/1320

a = 0.1667

So,b = 2 x 0.1667 = 0.3334

c = 1 - (3 x 0.1667)

c = 1 - 0.5

c = 0.5

Thus,

S1 = 12480a = 12480 x 0.1667 ≈ $2080

S2 = 25,440a = 25440 x 0.1667 ≈ $4241

S3 = 13080 - 39240(0.1667) ≈ 6539

So, $2080 was invested in the savings account, $4241 was invested in the bond account, & $6539 was invested in the money fund.

3 0
3 years ago
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A movie theater has a capacity of 241. The theater chargers $5 for children, $7 for students and $12 for adults. There are half
STatiana [176]

70(5) + 175(8) + 35(4) =

350 + 1400 + 140 = 1890

7 0
3 years ago
What is 25 of 108 in a percent
Georgia [21]

Answer:

I think its 27

Step-by-step explanation:

5 0
3 years ago
A 5.ft tall man casts a shadow along the ground that is 8 ft. long. At the same time a giraffe casts a shadow that is 12 ft. lon
forsale [732]

Answer :  7.5 ft

Step-by-step explanation:

when the length of the shadow is 8ft, the actual height of the man = 5ft

8:5

let the giraffe be 'x' ft tall.

if the length of the shadow is 12ft, actual height = x ft

12:x

8:5 x 12:x

\frac{8}{5} × \frac{12}{x}

x= \frac{15}{2}

x=7.5 ft

Therefore, the giraffe is 7.5ft tall.

4 0
1 year ago
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Enter <,>,= to make the problem true -19 5/6 _ -20 1/6
NemiM [27]

Answer:

>

..................................................................

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