Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.
A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
.. (A +C)/2 = ((0, 0) +(p, 0))/2 = (p/2, 0) = B'
The midpoint A' is
.. (B +C)/2 = ((m, n) +(p, 0))/2 = ((m+p)/2, n/2) = A'
B) The slope of the line between (x1, y1) and (x2, y2) is given by
.. slope = (y2 -y1)/(x2 -x1)
Using the values for A and A', we have
.. slope = (n/2 -0)/((m+p)/2 -0) = n/(m+p)
C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
.. y -0 = (n/(m+p))*(x -0)
.. y = n*x/(m+p)
D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
.. (x, y) = ((m+p)/3, n/3)
Putting these into our equation, we have
.. n/3 = n*((m+p)/3)/(m+p)
The expression on the right has factors of (m+p) that cancel*, so we end up with
.. n/3 = n/3 . . . . . . . true for any n
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* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.
The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.
Answer: 6 seconds
Step-by-step explanation:
Time Jabal (2.5mps) Michael (5mps)
Start 15 0
1 sec 17.50 5
2 20 10
3 22.5 15
4 25 20
5 27.5 25
6 30 30
7
8
9
10
Answer: base a=2ft
height hₐ=5ft
Step-by-step explanation:
use equation for area of triengle
A=a*hₐ/2
hₐ-height of tringle
a-base of triangle
hₐ=a+3
A=a(a+3)/2
2A=a²+3a
A=5ft
2*5=a²+3a
a²+3a-10=0
a=(-3±√9+40)/2
a=(-3±7)/2
a=-5ft
a=2 ft
hₐ=2+3=5ft
Answer:
2x−5y=12
y = 2/5x + −12/5
Answer is x = 5/2y + 6 because....
First, Add 5y to both sides.
2x − 5y + 5y = 12 + 5y
Then, Divide both sides by 2.
Therefor, your answer is going to be x = 5/2y + 6
* Hopefully this helps:) Mark me the brainliest:)!!!
