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3 years ago

Simplify:4sqrt400/4sqrt5. Show your work.

Mathematics

2 answers:

Deffense [45]3 years ago

7 0

$\frac{4 \sqrt{400} }{4 \sqrt{5} } = \frac{ \sqrt{400} }{ \sqrt{5} } = \\ \frac{20}{ \sqrt{5} } * \frac{ \sqrt{5} }{ \sqrt{5} } = \frac{20 \sqrt{5} }{5} } = 4 \sqrt{5}$
Thank you.

Softa [21]3 years ago

4 0

Simplify:4sqrt400/4sqrt5. Show your work.

Answer: This problem is simple. The process is a little long so in order to provide a good answer I will provide an attachment were all the steps are shown and the notes that are required to understand how to arrive to that answer. Please see attqchment.

I hope it helps, Regards.

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The Vice President Of Sales Took A Client Out To Lunch. If The Lunch Was $44 And She Gave A 20% Tip, How Much Money Did She Spen

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4 years ago

Based upon a smaller sample of only 170 st. paulites, what is the probability that the sample proportion will be within of the p

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Given that in 2008 the Better Business Bureau settled 75% of complaints they received (USA Today, March 2, 2009). Suppose you have been hired by the Better Business Bureau to investigate the complaints they received this year involving new car dealers. You plan to select a sample of new car dealer complaints to estimate the proportion of complaints the Better Business Bureau is able to settle. Assume the population proportion of complaints settled for new car dealers is .75, the same as the overall proportion of complaints settled in 2008.

Part a) :

Suppose you select a sample of 450 complaints involving new car dealers. Show the sampling distribution of (to 4 decimals).

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Therefore, the sampling distribution has a proportion of 0.75 and a standard error of 0.0204.

Part b) :

Based upon a sample of 450 complaints, what is the probability that the sample proportion will be within .04 of the population proportion (to 4 decimals)?

The probability that the sample proportion will be within 0.04 of the population proportion is given by:

$P(p\ \textless \ 0.75\pm0.04)=2P\left(z\ \textless \ \frac{0.04}{0.0204} \right)-1 \\ \\ 2P(z\ \textless \ 1.961)-1=2(0.97505)-1=1.9501-1 \\ \\ =\bold{0.9501}$

Therefore, the probability that the sample proportion will be within .04 of the population proportion is 0.9501.

Part C:

Suppose you select a sample of 200 complaints involving new car dealers. Show the sampling distribution of (to 4 decimals).

Population proportion = 0.75
sample size. n = 200
$Standard\ error=\sqrt{\frac{p(1-p)}{n}} \\ \\ =\sqrt{\frac{(0.75)(0.25)}{200}} = 0.0306$

Therefore, the sampling distribution has a proportion of 0.75 and a standard error of 0.0306.

Part D):

Based upon the smaller sample of only 200 complaints, what is the probability that the sample proportion will be within .04 of the population proportion (to 4 decimals)?


The probability that the sample proportion will be within 0.04 of the population proportion is given by:

$P(p\
 \textless \ 0.75\pm0.04)=2P\left(z\ \textless \ \frac{0.04}{0.0306} 
\right)-1 \\ \\ 2P(z\ \textless \ 1.306)-1=2(0.90429)-1=1.80858-1 \\ \\
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Therefore, the probability that the sample proportion will be within .04 of the population proportion is 0.8086.

8 0

3 years ago

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Answer:

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y = -4

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3 years ago

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Answer:

x = 10

Step-by-step explanation:

9 is to 45 as 2 is to x

9 ---- 45

2 ---- x

x = 2 . 45 / 9

x = 10

3 0

3 years ago

Read 2 more answers