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True [87]
3 years ago
14

The current in a wire is 4.00A. How much time is needed for 1 mole of electrons (6.02×1023 electrons) to pass a point in the wir

e?
Physics
1 answer:
scZoUnD [109]3 years ago
8 0

Answer:

t= 24080 s

Explanation:

Given that

Current in the wire ,I = 4 A

The charge ,q = 6.02 x 10²³ e C

We know that

I=\dfrac{q}{t}

I=Current  

q=Charge

t=time

t=\dfrac{q}{I}

Now by putting the values in the above equation we get'

t=\dfrac{6.02\times 10^{23}\times 1.6\times 10^{-19}}{4}\ s

t= 24080 s

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A 49 N coconut is in a 15 m tree. What is te potential energy of the coconut?
eduard

Answer:

735 J

Explanation:

From the question given above, the following data were obtained:

Weight (W) = 49 N

Height (h) = 15 m

Potential energy =?

Potential energy is simply defined as the product of weight of the object and height to which the object is raised. Mathematically, it is expressed as:

Potential energy = weight × height

With the above formula, we can obtain the potential energy of the coconut as follow:

Weight (W) = 49 N

Height (h) = 15 m

Potential energy =?

Potential energy = weight × height

Potential energy = 49 × 15

Potential energy = 735 J

Thus, the potential energy of the coconut is 735 J

4 0
3 years ago
A uniform metre rule of mass 100g balance the 40cm mark when a mass x is placed at the 20cm mark
vivado [14]

Answer:

X = 50 g

Explanation:

Please see attached photo for explanation.

From the attached photo,

Anticlock–wise moment = X × 20

Clockwise moment = 100 × 10

Anticlock–wise moment = clockwise moment

X × 20 = 100 × 10

X × 20 = 1000

Divide both side by 20

X = 1000 / 20

X = 50 g

Therefore, the value of X is 50 g

6 0
3 years ago
Which of the following is an elastic collision?
fiasKO [112]
D is also an example
3 0
3 years ago
Read 2 more answers
How does all body systems work yo maintain homeostasis
Grace [21]
Your brain controlls your body to move
8 0
3 years ago
Assume a planet is a uniform sphere of radius R that (somehow) has a narrow radial tunnel through its center. Also assume we can
katovenus [111]

Answer:

Explanation:

Let mass of the apple be m . Force on it at surface of the planet can be expressed as follows

F_R  = G Mm / R²

Where M is mass of the planet.

Let at at height h the gravitational force on apple be 0.3 F_R

0.3 F_R  = G Mm / ( R +h)²

Dividing the two equation

1 / 0.3  =  ( R +h)²/ R²

( R +h)/ R = 1.825

h = .825 R

b )

If we go deep inside the planet to get force on apple equal to .3 F_R

.3 F_R = G  4/3 π ( R - h )³ d m / (R-h)²         [ d is density of planet ]

.3 F_R = G  4/3 π ( R - h ) d m

F_R  = G Mm / R²

F_R  = G 4/3πR³d m / R²

F_R  = G 4/3πR d m

dividing two equations

0.3 =  ( R - h ) / R

h = .7 R

7 0
3 years ago
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