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ryzh [129]
3 years ago
10

A 9.5 v battery supplies a 3.5 ma current to a circuit for 6.0 h . part a how much charge has been transferred from the negative

to the positive terminal?
Physics
1 answer:
dmitriy555 [2]3 years ago
3 0
The total time is (1h=3600 s): 
\Delta t=6.0 h=21600 s
The current intensity I is the amount of charge Q that passes through a certain point in a time \Delta t:
I= \frac{Q}{\Delta t}
Since we know the current, I=3.5 mA=0.0035 A, we can find how much charge has been trasferred from one terminal to the other in 6 hours:
Q= I \Delta t=(0.0035 A)(21600 s)=75.6 C
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Answer:

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Explanation:

First to all, let's gather the data. We know that both rods, have the same length. Now, the expression to use here is the following:

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This is the equation that describes the relation between speed of a pulse and a force exerted on it.

the value of "u" is:

u = m/L

Where m is the mass of the rod, and L the length.

Now, for the rod 1:

V1 = √F/u1 (1)

rod 2:

V2 = √F/u2 (2)

Now, let's express V1 in function of V2, because we know that V1 is 1.4 times the speed of rod 2, so, V1 = 1.4V2. Replacing in the equation (1) we have:

1.4V2 = √F/u1 (3)

Replacing (2) in (3):

1.4(√F/u2) = √F/u1 (4)

Now, let's solve the equation 4:

[1.4(√F/u2)]² = F/u1

1.96(F/u2) =F/u1

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1.96 = m2/m1 (6)

But we need m1/m2 so:

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Answer

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