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My name is Ann [436]
3 years ago
11

A cheetah has an acceleration rate of 5.80 m/s2 . What is the cheetah’s final velocity after 7.80 seconds, if initially, his vel

ocity is 3.50 m/s?
Physics
1 answer:
Olegator [25]3 years ago
4 0

Answer:

you got holbrook huh

Explanation:

me too

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Isaac Newton’s investigations of gravity explained which of the following?
Umnica [9.8K]

C. Gravity acts on all objects in the universe.

Explanation:

Isaac Newton with his studies understood that the force of gravity acts on all objects with mass in the universe, and it is the same force that causes an apple to fall from a tree and that keeps the Earth in motion around the Sun.

Newtons also created a formula that allows us to calculate the force of gravity between two objects:

F=G\frac{m_1 m_2}{r^2}

where

G is the gravitational constant

m1 and m2 are the masses of the two objects

r is the separation between the two objects

4 0
4 years ago
Read 2 more answers
A train is moving with a velocity of 20 m/s. when the brakes are applied the acceleration is reduced to -0.6 m/s².calculate the
Serhud [2]

Answer:

x = 333.33 [m]

Explanation:

To solve this problem we must use the following kinematics equation.

v_{f}^{2} = v_{i}^{2}-(2*a*x)

where:

Vf = final velocity = 0

Vi = initial velocity = 20 [m/s]

a = desacceleration = 0.6 [m/s^2]

x = distance [m]

Note: the final speed is zero as the body finishes its movement.

Now replacing:

0 = (20)^2 - (2*0.6*x)

1.2*x = 400

x = 333.33 [m]

3 0
3 years ago
A block measure 10 cm by 10 cm by 5 cm , what is it’s volume
Lina20 [59]
I think it is 500 cm. Hope I helped!
5 0
4 years ago
a 120 ohm resistor, a 60 ohm resistor, and a 40 ohm resistor are connected in parallel to a 120 volt power source. what is the c
Ber [7]
Answer:
\frac{1}{r \: total} = \frac{1}{120} + \frac{1}{60} + \frac{1}{40} \\ \frac{1}{r \: total} = \frac{1 + 2 + 3}{120} = \frac{6}{120} = \frac{1}{20} \\ r \: total = 20 \: ohms
Knowing V=ri
then, 120=i×20 --> i=6 A
3 0
3 years ago
A moving particle fragments or decays into a particle moving at .53c, mass 135 MeV/c2, and a particle moving at .98c, mass 938 M
Svetllana [295]

Answer:

M = 1073 Mev/c2

u = 0.95 C        

Explanation:

given data:

m1 =135 Mev/c2

v1 = 0.53 c

m2 = 938 Mev/c2

v2 = 0.98 c

from conservation of momentum principle we have

\frac{mu}{\sqrt{1-\frac{u^2}{C^2}}} = \frac{m1v1}{\sqrt{1-\frac{V1^2}{C^2}}} +\frac{m1v1}{\sqrt{1-\frac{V2^2}{C^2}}}

\frac{mu}{\sqrt{1-\frac{u^2}{C^2}}} = \frac{135*0.53c}{0.848} +\frac{938*0.98c}{0.2}

\frac{mu}{\sqrt{1-\frac{u^2}{C^2}}} = 4680.6 C   ...............1

Total mass of INITIAL particle M   =m1+m2 = 1073 Mev/c2

using equation 1

\frac{1073 u}{\sqrt{1-\frac{u^2}{C^2}}}= 4680.6C

solving for u we get

u = 0.95 C          

8 0
4 years ago
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