893 hundreds x 85 tens =

Mathematics

2 answers:

cricket20 [7]3 years ago

8 0

The answer is 75,905

Sveta_85 [38]3 years ago

6 0

Answer:

75,905,000 or 75,905 thousands.

Step-by-step explanation:

We are asked to find the product of the given quantities.

893 hundreds would be $893\times 100=89300$ .

85 tens would be $85\times 10=850$ .

The product of both numbers would be:

$89,300\times 850=75,905,000$ .

Therefore, our required product would be 75,905,000 or 75,905 thousands.

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Your friend claims that because each midsegment is half as long as the corresponding side of the triangle, the perimeter of the

lora16 [44]

Answer:
The claim is correct

Explanation:
Assume the given triangle ABC
perimeter of triangle ABC = AB + BC + CA ............> I

Now, we have:
D is the midpoint of AB, this means that:
AD = DB = (1/2) AB ..........> 1
E is the midpoint of AC, this means that:
AE = EC = (1/2) AC ...........> 2
DE is the midsegment in triangle ABC, this means that:
DE = (1/2) BC ...........> 3
perimeter of triangle ADE = AD + DE + EA
Substitute in this equation with the corresponding lengths in 1,2 and 3:
perimeter of triangle ADE = (1/2) AB + (1/2) BC = (1/2) AC
perimeter of triangle ADE = (1/2)(AB+BC+AC) .........> II

From I and II, we can prove that:
perimeter of triangle ADE = (1/2) perimeter of triangle ABC
Which means that:
perimeter of midsegment triangle is half the perimeter of the original triangle.

Hope this helps :)