Answer:
C) 8 and 9
Step-by-step explanation:
We know that 70 is between two perfect squares.
The square numbers 64 and 81 can help us solve this question.
64<70<81
We take square root to get:

We simplify this to get:

Therefore √70 is between 8 and 9.
The correct option is C.
Answer:
A.) 90 clockwise
E.)270 Counter Clockwise
Step-by-step explanation:
A.) Ro, -90 Rotation about the origin (0,0) 90° clockwise
(x, y) ⇒ (y, -x)
(-1, 5) ⇒ (5, 1)
E.) Ro, 270 Counter Clockwise
(x, y) ⇒ (y, -x)
(-1, 5) ⇒ (5, 1)
The answer is 84 because of process priority
Ab = (7x-6) → b = (7x-6)/a (1)
bc = (12-2x) → b = (12-2x)/c (2)
Since (1) = (2) → (7x-6)/a = (12-2x)/c OR a/c = (7x-6)/(12-2x) (3)
Multiply both numerators of (3) by the SQUARE of their respective denominators;
(a*c²)/c = (7x-6)(12-2x)²/(12-2x)
Now simplify:
ac = (7x-6)(12x-2x) or ac = -14x² + 96x - 72
Answer: She would need 32
Step-by-step explanation: