<span>y=x-4
y=-x+6
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Substitute x - 4 for y in </span>y=-x+6
x-4=-x+6<span>
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Add X on each side
</span><span>x-4+x</span>=-<span>x+6+x
</span>2x - 4 = 6
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Add 4 on each side
<span>2x-4+4</span>=<span>6+4
</span>2x = 10
------------------------------------------------
Divide by 2 on each side
2x ÷ 2 = 10 ÷ 2
x = 5
Now we have X
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To find Y we substitute 5 for x in y=<span>x-<span>4
</span></span>y = 5 - 4
y = 1
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Your answers are Y = 1 and X = 5
It is incorrect because when you times a negative by a positive. It is a negative number.
First you need to see that this is a quadratic. I need.to put all of the values on one side of equation to see what I got.
6r^2 + 7r + 8 = 6
6r^2 + 7r + 2 = 0
Now this one is difficult to factor so i will use quadratic equation:
[-b (+-) sqrt (b^2 - 4ac)] / (2a)
we know that a b and c are in a quadratic at these positions.
ax^2 + bx + c
so
[-7 (+-) sqrt (7^2 -(4)(6)(2)] / (2) (6)
[-7 (+-) sqrt (49 - 48)] / 12
[-7 (+-) 1] /12
split into the + and - for 2 answers
(-7 + 1) / 12
-6/12
-1/2
And
(-7 -1) /12
-8 / 12
-2/3
those are.the 2 answers
But but it says largest so -1/2
Domain: (-∞,∞) or All real numbers
Range: (-∞,∞) or All real numbers
Answer:
x(1,4) Y(2,3) and Z(5,y)
Step-by-step explanation:
